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xenn [34]
4 years ago
9

Help me pleaseeee!!!

Mathematics
1 answer:
Colt1911 [192]4 years ago
3 0

Answer:

Slope = 3

Step-by-step explanation:

Because it increases by 3 each time.

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This is the last question but I need the answer please help
Nastasia [14]

Answer:

2

Step-by-step explanation:

Identify the coordinates as x1, y1 and x1, y2. Solve by using the formula of slope(gradient)

7 0
2 years ago
What is the answer to 4+4-(5-1)
Zanzabum
Your answer would be 4 you go with P.E.M.D.A.S so (5-1)= 4 then 4+4=8-4=4
6 0
4 years ago
Use the graph below to fill in the blank with the correct number:
Alik [6]
Let
A(-3,0) \\ B(-2,2) \\ C(0,1) \\ D(1,-2)

we know that

Point A
A(-3,0) \\ for x=-3 \\ f(-3)=0

Point B
B(-2,2) \\ for x=-2 \\ f(-2)=2

Point C
C(0,1) \\ for x=0 \\ f(0)=1

Point D
D(1,-2) \\ for x=1 \\ f(1)=-2

therefore

the answer is
f(0)=1
4 0
3 years ago
Read 2 more answers
How do you add and subtract decimals as easily as you do whole numbers?
Gwar [14]
You can also multiply the decimals by a multiple of 10 to turn them I to whole numbers. Just make sure you multiply them both by the same multiple of 10 and divide them back before you write your answer!
8 0
3 years ago
The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per
ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that \mu = 2

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902

P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176

1.76% probability that in one hour more than 5 clients arrive

8 0
3 years ago
Read 2 more answers
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