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KIM [24]
3 years ago
7

|6m+5|=10 That's my question

Mathematics
1 answer:
Brut [27]3 years ago
6 0

Answer:Just calculate this:

A) 2(3m + 5) = 6m + 10 - incorrect

B) -2(5 - 3m) = -10 + 6m - could be correct

C) 2(3m - 10) = 63 - 20 - incorrect

So the correct answer has to be B: -10 + 6m is the same as 6m - 10 hopes this help

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A coin collection is made up of 34 coins comprised of nickels and dimes. The total value of the collection is $1.90. How many di
riadik2000 [5.3K]

Answer:

x = nickels

y= dimes

x + y = 34

.05x + .10y= $1.90

-.10x - .10y = -3.40

-.05x + .10y = 1.90

-.05x = -1.50

x = 30 nickels

30 + y = 34

y = 4 dimes

(3,4)

7 0
3 years ago
Given: ∠AOC, ∠BOC - complementary angles
34kurt

Answer:

  • 30
  • COB . . . . or . . . . BOC

Step-by-step explanation:

The reason given on the line of interest is "substitution," so the problem boils down to determining what was substituted for what. The previous statement says ...

  AOC + COB = 90

and the first part of the statement we're to complete has BOC + ___.

We see from the given statements that m∠AOC = m∠BOC + 30°, so it appears that is the substitution that has been made: AOC has been replaced by BOC + 30.

This means the first blank is filled with 30.

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The second part of the previous statement is ...

  AOC + COB = 90

so we believe this (COB) should go in the second blank.

__

Then the line of interest would read ...

  BOC + 30 + COB = 90

_____

<em>Comment on the problem</em>

There is a curious mix of notations here. Usually, (as in the beginning of this problem) we refer to the measure of an angle using "m∠" in front of the angle designator, and we use a degree symbol to indicate the units of that measure. Part-way through the problem statement written here, those notations were dropped, and we're to assume they are intended. IMO, this is a poor way to demonstrate careful problem solving.

The substitution given for AOC is BOC+30, but the line into which that is substituted has AOC +COB = 90. This means the equation after substitution is ...

  BOC +30 +COB = 90

Since BOC and COB are the same angle, we can sort of fudge the "algebra" to get to  BOC=30, but if the problem were more carefully written, the angle would be referred to by consistent nomenclature:

  m∠AOC + m∠BOC = 90° . . . . . . . . . preferred angle designations

  (m∠BOC + 30°) + m∠BOC = 90° . . . . substitution for m∠AOC

  2(m∠BOC) = 60° . . . . . . algebra (subtract 30°, collect terms)

  m∠BOC = 30° . . . . . . . . algebra (divide by 2)

3 0
3 years ago
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Aneli [31]

Answer:

See explanation and attachment.

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Algebra tiles come with different colors and sizes. Each size is equivalent to a degree of different monomials.

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