Using the fact that cos is 2π-periodic, we have
That is, 
for any 
and integer 
.
We get 2 solutions in the interval [0, 2π] for 
and 
,
The best thing is to have a ruler with the appropriate units to construct these triangles;)
Answer:
Step-by-step explanation:
D. violates the Law of Sines.
Answer:
Step-by-step explanation:
When,x= -1
Now,
f(-1)=-(-1)^2+6
=1+6
=7
Hope it helped you.
Answer:
8\sqrt{2}\ units.
Step-by-step explanation:
Use the trignometric property.
sin\theta = \frac{Perpendicular}{Hypotenuse}
Perpendicular = 8
Hypotenuse = h
\theta = 45^{\circ}
sin\ 45^{\circ} = \frac{1}{\sqrt{2}}
\frac{1}{\sqrt{2}} = \frac{8}{h}
h = 8\sqrt{2}\ units
Hope I helped you! x
