Given that JKLM is a rhombus and the length of diagonal KM=10 na d JL=24, the perimeter will be found as follows;
the length of one side of the rhombus will be given by Pythagorean theorem, the reason being at the point the diagonals intersect, they form a perpendicular angles;
thus
c^2=a^2+b^2
hence;
c^2=5^2+12^2
c^2=144+25
c^2=169
thus;
c=sqrt169
c=13 units;
thus the perimeter of the rhombus will be:
P=L+L+L+L
P=13+13+13+13
P=52 units
The antiderivate of 5x is 5x^2 / 2 .
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Answer:
C.
Step-by-step explanation:
the farther you get from Earth, the less the gravitational force i, so if your in space,<em><u> </u></em><em><u>you will have more weight next to earth than you will next to the moon</u></em><em><u>.</u></em>
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If the 3 is an exponent, then the person above me is right.
