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11Alexandr11 [23.1K]
4 years ago
13

Find the distance between the two points. Round to the nearest tenth if necessary.

Mathematics
1 answer:
prohojiy [21]4 years ago
8 0

Answer:

the answer to the nearest tenths is 7.8

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Is all the numbers 1-99 back to back divisible by 9
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Technically, every number is divisible by any number. While it most times results in a decimal/fraction, that decimal/fraction is the answer.
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Question 3 This questions requires you to examine computational differences for methods used to calculate sample variation. You
Licemer1 [7]

Answer:

sigma formulas are executed by using for loop to sum all the values.

public class H4_Q3{

public static void main(String[] args)

{

//Part a

double[] values = {100000000.6, 99999999.8, 100000002.8, 99999998.5, 100000001.3};

int n = values.length;

//Part b;

double sum = 0;

double sample_average = 0;

double sample_variance = 0;

int i = 0;

for(i = 0; i < n; i++)

{

sum = sum + values[i];

}

sample_average = sum/n;

for(i = 0; i < n; i++)

{

sample_variance = sample_variance + (Math.sqrt(values[i]) - sample_average);

}

System.out.println("Sample variance (Part b formula): "+sample_variance);

//Part c

double sum_squared = 0;

double sum_values = sample_average;

for(i = 0; i < n; i++)

{

sum_squared = sum_squared + Math.sqrt(values[i]);

}

sum_squared = sum_squared/n;

sample_variance = (sum_squared - Math.sqrt(sum_values)) * (n/ (n - 1));

System.out.println("Sample variance (Part c formula): "+sample_variance);

//Part d

sample_variance = 0;

double[] M = new double[n];

double[] S = new double[n];

M[0] = values[0];

S[0] = 0;

i = 1;

while(i < n)

{

M[i] = M[i-1] + ((values[i] - M[i-1])/i+1);

S[i] = S[i-1] + (values[i] - M[i-1]) * (values[i] - M[i]);

i++;

}

System.out.println("Sample variance (Part d formula): "+S[n-1]/n);

}

}

8 0
3 years ago
-7.8 + 4.2 - 6.5 What is the value of the expression below?
Juli2301 [7.4K]

Answer:

-10.1

Step-by-step explanation:

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3 years ago
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A=D+qm, solve for q.........
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Step-by-step explanation:

A=D+qm

qm = A - D

q =(A-D) /m

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3 years ago
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Use the ratio test to determine whether the series is convergent or divergent.
Kitty [74]

Answer:

Divergent

Step-by-step explanation:

Given series has general term as

\frac{2^n}{n^2}

n+1 th term =\frac{2^(n+1)}{(n+1)^2}

WE have to check whether this series converges or diverges

Let us use ratio test

Ratio of n+1 th term to nth term

=\frac{2n^2}{(n+1)^2} =\frac{2}{(1+\frac{1}{n} }^2

by dividing numerator and denominator by n square

Take limits as n tends to infinity

The ratio tends to 2

Since ratio >2, the series diverges

4 0
4 years ago
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