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omeli [17]
2 years ago
9

Perimeter of semicircular

Mathematics
2 answers:
zysi [14]2 years ago
4 0

Answer:

half of the circumference plus the diameter.

Step-by-step explanation:

Lisa [10]2 years ago
3 0

Step-by-step explanation:

pie radius plus two pie radius

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A total of 579 tickets were sold for the school play they were either adult tickets or student tickets. there were 71 fewer stud
stepan [7]

Answer: 325

Step-by-step explanation:

Student tickets: x

Adult tickets: x + 71

Total: 579

x + x + 71 = 579

2x + 71 = 579

2x = 579 - 71

2x = 508

x = 508/2

x = 254

Adult tickets = x + 71 = 254 + 71 = 325

P.S. Hope it helps. If you have any questions, feel free to ask them here. I'll be happy to help! Have a wonderful day!

4 0
2 years ago
Jupiter is 3 times the size of Neptune. If the diameter of Jupiter is 88,736 miles, what is the diameter of Neptune?
blagie [28]

Answer:

29,579 miles

Step-by-step explanation:

Divide Jupiter`s diameter by 3 which is 29,578.66 miles rounded up is 29,579 miles

4 0
3 years ago
Determine whether or not F is a conservative vector field. If it is, find a function f such that F = ∇f. (If the vector field is
gavmur [86]

If

\nabla f=(ye^x+\sin y)\,\vec\imath+(e^x+x\cos y)\,\vec\jmath

then

\dfrac{\partial f}{\partial x}=ye^x+\sin y\implies f(x,y)=ye^x+x\sin y+g(y)

Differentiating with respec to y gives

\dfrac{\partial f}{\partial y}=e^x+x\cos y=e^x+x\cos y+g'(y)

\implies g'(y)=0\implies g(y)=C

So F is indeed conservative, and

f(x,y)=ye^x+x\sin y+C

3 0
3 years ago
Three friends decide to pool their money together to buy a video game. John has $12. Stephanie has $15, and Laura has $10. How m
lesantik [10]

Answer:

37$

Step-by-step explanation:

this problem can actually be solved with a calculator!

12 + 15 + 10 =

37

8 0
3 years ago
Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = yzi + 4xzj + ex
natima [27]

Answer:

The result of the integral is 81π

Step-by-step explanation:

We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S

Finding the curl of F.

Given F(x,y,z) = < yz, 4xz, e^{xy} > we have:

curl \vec F =\left|\begin{array}{ccc} \hat i &\hat j&\hat k\\ \cfrac{\partial}{\partial x}& \cfrac{\partial}{\partial y}&\cfrac{\partial}{\partial z}\\yz&4xz&e^{xy}\end{array}\right|

Working with the determinant we get

curl \vec F = \left( \cfrac{\partial}{\partial y}e^{xy}-\cfrac{\partial}{\partial z}4xz\right) \hat i -\left(\cfrac{\partial}{\partial x}e^{xy}-\cfrac{\partial}{\partial z}yz \right) \hat j + \left(\cfrac{\partial}{\partial x} 4xz-\cfrac{\partial}{\partial y}yz \right) \hat k

Working with the partial derivatives

curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(4z-z\right) \hat k\\curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k

Integrating using Stokes' Theorem

Now that we have the curl we can proceed integrating

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot \hat n dS

where the normal to the circle is just \hat n= \hat k since the normal is perpendicular to it, so we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S \left(\left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k\right) \cdot \hat k dS

Only the z-component will not be 0 after that dot product we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3z dS

Since the circle is at z = 3 we can just write

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3(3) dS\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 9\int \int_S dS

Thus the integral represents the area of a circle, the given circle x^2+y^2 = 9 has a radius r = 3, so its area is A = \pi r^2 = 9\pi, so we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = 9(9\pi)\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 81 \pi

Thus the result of the integral is 81π

5 0
3 years ago
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