55/9 = 6.11
57/7 = 8.14
41/5 = 8.2
65/8 = 8.125
The answer is 41/5 is larger than 8.15
Answer:
0.018 is the probability that a randomly selected college student has an IQ greater than 131.5
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 15
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
a) P(IQ greater than 131.5)
P(x > 131.5)
Calculation the value from standard normal z table, we have,
0.018 is the probability that a randomly selected adult has an IQ greater than 131.5
I personally think this:
length = 10 feet
width = 10 feet
