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tatiyna
3 years ago
15

Plz help me I don’t understand this

Mathematics
2 answers:
Snezhnost [94]3 years ago
4 0
I believe the answer is 31/10
Firlakuza [10]3 years ago
3 0

The answer should be 31/10

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Convert the standard equation to vertex form.<br> f(x) = 3x^2+ 18x – 7
natima [27]
Find the vertex form Y=3(x+3^2-34
5 0
2 years ago
What is the justification for each step in the solution of the equation?<br><br> 5x−42=2x−1
yanalaym [24]

Answer:

<h3>39.6</h3>

Step-by-step explanation:

collecting like terms we have:

5x-2x=-1+42

equating the terms..we have:

3x=41

divide both sides by the Co-efficient of x:

3x\3=42\3

x=39.6

7 0
2 years ago
Read 2 more answers
Which expression represents a number that is four times as large as the sum of 8 and 160?
DedPeter [7]
ANSWER: x = 4 ( 8 + 160 )

STEP BY STEP:

Let's start by getting a variable to represent the number. Let's use x. ⇩

x=

Now we know that there is a sum of 8 and 160. Let's add them to each other ⇩

x= 8 + 160

Now we know that this will be multiplied. Let's put parentheses around the addition to symbolize this.

X= (8 + 160)

Finally multiply this by four, making your equation

x= 4 (8 + 160)

I don't know the options but from looking at the problem I'm assuming the answer is
x = 4 ( 8 + 160 )

8 0
3 years ago
Segments AB and CD coincide.
Westkost [7]

Answer: it’s the first one

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Suppose that you take 120 mg of an antibiotic every 4 hr. The​ half-life of the drug is 4 hr​ (the time it takes for half of the
vodomira [7]

Answer:

The steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Step-by-step explanation:

Let the amount of antibiotic in one's bloodstream be given as Aₙ (where n = the number of half lives since the start of usage)

Let's follow the time line of events.

At t = 0 hr, the drug is taken

A₀ = 120 mg

At t = 4 hrs, n = 1, the drug is taken again

A₁ = (0.5×A₀) + 120

A₁ = (0.5×120) + 120 = 180 mg

At t = 8 hrs, n = 2, the drug is taken again,

A₂ = (0.5×A₁) + 120

A₂ = (0.5×180) + 120 = 210 mg

At t = 12 hrs, n = 3, the drug is taken again

A₃ = (0.5×A₂) + 120

A₃ = (0.5×210) + 120 = 225 mg

At this point, it becomes evident that at t = 4n hrs, n = n i.e. n half lives later, the general formula for the amount of the antibiotic in the bloodstream is

Aₙ = 0.5Aₙ₋₁ + 120

where Aₙ₋₁ = The amount of antibiotic in the bloodstream at the time t = 4(n-1) and (n-1) half lives later.

For infinite series, that are increasing in this order, as the value of n --> ∞,

Aₙ = Aₙ₋₁ = K

And our general formula becomes

K = 0.5K + 120

0.5K = 120

K = (120/0.5)

K = 240 mg

Hence, the steady state amount of antibiotic in the bloodstream when t --> ∞ is 240 mg.

Hope this Helps!!!

5 0
3 years ago
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