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Eddi Din [679]
3 years ago
13

If the area of a rectangle is 50m^2 what is the perimeter?

Mathematics
2 answers:
elixir [45]3 years ago
4 0

Answer:

Step-by-step explanation:

2l+2w= 50

l= 4w-8

2 (4W - 8) + 2W = 50.

2 (4W - 8) + 2W = 50

8W - 16 + 2W = 50

10W - 16 = 50

10W = 66

W = 6.6 meters

Solve for L

L = 4W - 8

L = 4 (6.6) -8

L = 26.4 - 8

L = 18.4

Dimensions are 6.6 and 18.4

I hope this is right

nika2105 [10]3 years ago
3 0

It's most likely 30 m

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Gemiola [76]

Albert bought 2 pounds of catfish and 2 pounds of salmon

Let c represent the amount of catfish in pounds and s represent the amount of salmon in pounds.

He spent a total of $12 on salmon and catfish and bought a total of 4 pounds.  Hence:

c + s = 4    (1)

4c + 2s = 12    (2)

Solving equations 1 and 2 simultaneously gives:

c = 2, s = 2

Albert bought 2 pounds of catfish and 2 pounds of salmon

Find out more on equation at: brainly.com/question/2972832

7 0
2 years ago
Pls help i will give brainliest
zlopas [31]
It is B because yiu solve
3 0
3 years ago
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
3 years ago
Determine the unknown angles in the diagram above. Please help!
Nana76 [90]

A

a and 143 are supplementary. So a + 143 = 180

a + 143 = 180              Subtract 143 from both sides.

a = 180 - 143

a = 37

B

b and 143 are vertically opposite angles and are equal

b = 143 degrees.

C

Interior angles on the same side of a transversal for parallel lines are supplementary

b + c = 180

143 + c = 180

c = 37

D

c + d + 85 = 180 degrees

37 + d + 85 = 180

d + 122 = 180

d = 180 - 122

d = 58

E

e = c They are vertically opposite.

e =37

F

All triangles have 180 degrees.

e + f + 90 = 180 degrees.

37 + f + 90 = 180

f  +  127 = 180

f = 180 - 127

f = 53

G

G and 48 are opposite 2 equal sides. So G and 48 are equal

G = 48

H

h + 48 + 48 = 180

h + 96 = 180

h = 84

K

K and H are supplementary

K + H = 180

k + 84 = 180

k = 95

M

m+ k + d  = 180

M + 95 +  58 = 180

M + 143 = 180

M = 37

P

the top angle is 2*m and 2m is bisected. You are using the m on the left.

P + 85 + M = 180

P + 85 + 37 = 180

P + 122 = 180

p = 180 - 122

p = 58

R

r + p are supplementary.

r + p = 180

r + 58 = 180

r = 180 - 58

r = 122

S

s + r + c + b = 360  All quadrilaterals have 360 degrees.

s + 122 + 37 + 143 = 360

s + 302= 360

s = 360 - 302

s = 58

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3 years ago
A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?
jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get  x^2 + y^2 + 6y                = 72.

x^2 is already a perfect square.  Focus on rewriting y^2 + 6y as the square of a binomial:  y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9  - 9              = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2.  Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

8 0
3 years ago
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