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nika2105 [10]
3 years ago
12

Solve the following radical: 5√13 - 9√13

Mathematics
1 answer:
tankabanditka [31]3 years ago
7 0
Answer is -12 hope I helped.
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Identify the type of pair of angles labeled as 1 and 2 in the figure.
myrzilka [38]

<em>Hey</em><em>!</em><em>!</em>

<em>1</em><em> </em><em>and </em><em>2</em><em> </em><em>are</em><em> </em><em>vertical</em><em> </em><em>angles</em><em>.</em>

<em>Vertically</em><em> </em><em>opp</em><em>osite</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>always</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>

7 0
2 years ago
Read 2 more answers
How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin and rolling a dice
dolphi86 [110]
The total number of outcomes of rolling a die      = 6
The total number of outcomes of  tossing a coin = 2

The total number of possible outcomes of executing both experiments is 6*2=12, which is also the number of leaves (end of the branch of a tree) on a tree diagram.
4 0
2 years ago
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A grocer has two kinds of tea, one selling for 80 cents per pound and the other selling for 60 cents per pound. How many pounds
ruslelena [56]
X*80+y*60= 50*74
x      +y      =50            | * ( -60)

80x  + 60y= 50*74
-60x  - 60y=-50*60
---------------------------
20x= 50*(74-60)=50*14
x=50*14/20=35 pounds of 80 cents tea
y=50-35=15 pounds of 60 cents tea
8 0
3 years ago
Can a variable be a constant
Sonja [21]

Answer: No

Step-by-step explanation:

A variable is always denoted with a symbol (commonly x), and a variable means that it can change based on what you plug into the symbol

Constants must always stay the same, so variables can't be constants and constants can't be variables

8 0
3 years ago
Read 2 more answers
If perpendiculars from any point within an angle on its arms are equal, prove that it lies on the bisector of that angle
Oxana [17]
Your question can be quite confusing, but I think the gist of the question when paraphrased is: P<span>rove that the perpendiculars drawn from any point within the angle are equal if it lies on the angle bisector?

Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector

4 0
3 years ago
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