Answer:
Check the attached graph
Step-by-step explanation:
Given equation is 
.
Now we need to graph the given equation ..
Clearly it is not linear as equation is not of the form 
. So we need to find some points on given equation . by plugging some random values of x like -5,-3,1,... etc.
for x=-5, we get:
.
Hence first point is at (-5,-2). Similarly we can find more points and graph those points.
x can't be 0 as division by 0 is not defined so it will have vertical asymptote at x=0.
Since degree of numerator is less than degree of denominator so y=0 will be horizontal asymptote.
Now join those points by a curved line to get final graph.
Last one: Use employee identification numbers to randomly select 200 employees.
It's the most random.
27.5
Just divide 330 and 12 because 1 dozen is 12!
Answer:
x = - 3
y = - 2
Step-by-step explanation:
Start with the second equation. Switch
3y = 2x Divide by 3
3y/3 = 2x/3
y = 2x/3
Now go to the first equation. Put the value for y in the first equation.
x - 3(2x/3) = 3 Cancel the 3s on the left.
x - 2x = 3 Combine
-x = 3 Multiply by -1
-1(-x) = 3(-1)
x = - 3
Now go back to the original equation I have called the second equation
2x = 3y
2(-3) = 3y Put in - 3 for x
- 6 = 3y Divide by 3
-6 / 3 = y
y = - 2
