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3 years ago

ANSWER THIS FOR ME PLEASEEE !!

Mathematics

1 answer:

maw [93]3 years ago

6 0

Answer:

Its is the second bubble! Hope this is right!

Step-by-step explanation

They have 100 squares, 75 are shaded, Its a fraction 75 over 100!

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HELP IF RIGHT WILL MARK BRIANLIEST!! NO LINKS!!!!!!!

Brrunno [24]

Answer:

14 is the simplified answer, but the whole answer is 17 + -18/6

Step-by-step explanation:

Divide

−

18 by 6. h (−18) = 17 − 3 Subtract 3 from 17. h (−18)= 14

The final answer is 14.

8 0

3 years ago

Read 2 more answers

You need 12 gallons of paint to paint the exterior of your house. At one store the paint sells for $19.95 a gallon. At a second

nikklg [1K]

Answer:

it is $239.40 for $19.95 and 12 gallons and for $37.98 for 6 gallons it is $227.88. you would save $11.52

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Hey sorry to bother you but what is (x+4)^2

guapka [62]

X^2 + 8x + 16 is the answer

4 0

3 years ago

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The area of square C is 100 square units and the area of square B is 64 square units. What would be the area of square A?

rjkz [21]

Answer: The area of square A is 28 square units because the area is decreasing by 36 and the angles on each side is decreasing by 9

Step-by-step explanation:

100 divide by 4 sides = 25

64 divide by 4 sides = 16

28 divide by 4 sides = 7

7 0

2 years ago

Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D

viva [34]

Answer:

$\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C$

Step-by-step explanation:

So we have the indefinite integral:

$\int (\ln(x))^2dx$

This is the same thing as:

$=\int 1\cdot (\ln(x))^2dx$

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

$u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}$

Simplify:

$du=\frac{2\ln(x)}{x}dx$

And:

$dv=(1)dx\\v=x$

Therefore:

$\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx$

The x cancel:

$=x\ln(x)^2-\int2\ln(x)dx$

Move the 2 to the front:

$=x\ln(x)^2-2\int\ln(x)dx$

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

$=x\ln(x)^2-2\int 1\cdot\ln(x)dx$

Let u be ln(x) and let dv be (1)dx. Thus:

$u=\ln(x)\\du=\frac{1}{x}dx$

And:

$dv=(1)dx\\v=x$

So:

$=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)$

Simplify the integral:

$=x\ln(x)^2-2(x\ln(x)-\int (1)dx)$

Evaluate:

$=x\ln(x)^2-2(x\ln(x)-x)$

Now, we just have to simplify :)

Distribute the -2:

$=x\ln(x)^2-2x\ln(x)+2x$

And if preferred, we can factor out a x:

$=x(\ln(x)^2-2\ln(x)+2)$

And, of course, don't forget about the constant of integration!

$=x(\ln(x)^2-2\ln(x)+2)+C$

And we are done :)

8 0

3 years ago