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Juli2301 [7.4K]
3 years ago
15

Pls answer and show WORK pls do it right

Mathematics
1 answer:
adelina 88 [10]3 years ago
5 0

Answer:

4/6

Step-by-step explanation:

1/2 needs to be converted to sixths, so we would multiple the numerator and the denominator by 3, because 2 goes into 6, 3 times, then we would get 3/6 + 1/6, then just add, 1 + 3 = 4, and then you end up with 4/6. Have A Great Day!

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Kourtnie and kayla are sisters who are taking the same classes this semester: dre 098, chm 130/130a, and aca 122. if kourtnie ea
Volgvan
W are r are not valid grades. I have attached the table associated with this question

Answer:
GPA = 3.625

Explanation:
GPA stands for "Grade Point Average".
It can be easily calculated by dividing the total grade points with the total number of hours.
Taking a look at the table, we can find that:
Total grade points = 29
Total hours = 8
Therefore:
GPA = 29 / 8 = 3.625

Hope this helps :)

5 0
3 years ago
100000000000000000000000000000000000000000+53624785326348756348927563482564328965342875634289573264
Arlecino [84]

Answer:

5.3624785e+55

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which of the following is the equation of a line parallel to the line y = 4x + 1,
Lisa [10]

Answer:

y = 4x - 19

Step-by-step explanation:

The line is parallel to the line whose equation is;

y = 4x + 1

Parallel lines have the same slope so the slope of our line is 4.

The line passes through point (5,1)

Slope = change in y ÷ change in x

Taking another point (x,y) on the line,

Slope = \frac{y-1}{x-5} = 4

y - 1 = 4x - 20

y = 4x - 19

4 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
Manuel ate 1/3 of the cracker on a plate. His brother ate 1/4 of the cracker. their were 5 crackers left on the plate. How many
Lynna [10]
5 and 7/12 of a cracker
6 0
3 years ago
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