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LiRa [457]
2 years ago
8

Side's of a triangle to side of a square​

Mathematics
2 answers:
olga2289 [7]2 years ago
4 0
If your talking about ratios, it would be 3:4
Hope this helped! :)
Masja [62]2 years ago
3 0

Answer:

3:4

Step-by-step explanation:

there are 3 sides on a triangle and 4 on a square

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Points A, B, C, and D are connected by segments.
Verizon [17]

Answer:

c

Step-by-step explanation:

I think its c

I'm not sure

4 0
3 years ago
The mean of three numbers is 4 <br> Two of the numbers are 1, 9 <br> What is the missing number?
aliya0001 [1]

Answer:2

Step-by-step explanation: 9+1+2=12

12\3=4

ANSWER : 2

7 0
2 years ago
Read 2 more answers
During the national day celebrations.Asha decorates her balcony with serial lights of red,green and white colours.The red light
expeople1 [14]

If all three coloured lights blink together at 8:49 pm, they will blink together at 8:50 pm

<u>Solution:</u>

Given that the red light blinks at intervals of 4 seconds, the green at 5 seconds and the white at 6 seconds.

If all three colored lights blink together at 8:49 pm,

We have to find when will they blink together again?

First let us know, at what intervals they all together blink.

For that we have to find the lcm of 4, 5, 6.

L.C.M (4, 5, 6) = 2 x L.C.M(2, 5, 3)

As 2,3,5 are primes, we can’t take common further, so multiply all  

= 2 x 2 x 5 x 3

= 4 x 15  = 60

So, after every 60 seconds = 1 minute they will blink.

Then, after 8 : 49 pm, they will blink at 8 : 49 + 1 = 8 : 50 pm.

Hence, they all blink at 8 : 50 pm.

6 0
2 years ago
a corporation issues 1,200,000 shares of stock at its beginning to shareholders. how many shares must a shareholder own to have
weqwewe [10]
<span>A shareholder must own 600,001 shares to have majority.
</span><span>
</span>
6 0
2 years ago
Solve 15 ≥ -3x or 2/3 x ≥ -2.
hjlf
Solve each of the equations independently, then determine if the are continuous or discontinuous. 
15≥-3x [start here]
-5≤x    [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!]
x≥-5  [just turned around for analysis]

Next equation:
2/3x≥-2    [start here]
x≥-2(3/2)  [multiply both sides of the equation by the reciprocal, 3/2)
x≥-3

So, (according to the first equation) all values of x must be greater than, or equal to -5.

(According to the second equation) all values of x must be greater than, or equal to -3. 
So, when graphed on a number line, both equations graph in the same direction, so they are continuous.

4 0
2 years ago
Read 2 more answers
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