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Inessa05 [86]
3 years ago
12

I really need someone to help me out

Mathematics
1 answer:
elixir [45]3 years ago
3 0

All it takes for a relation to be a function is for each possible first number of a pair there's only one possible second number.


So if any of the sets has two pairs with the same first number, that one's not a function.


The last one has (3,2) and (3,5) so isn't a function.



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What is the slope of the line given by the equation y=-7X? O A 7 OB. 7 O c. -7 O D. 7​
Anna007 [38]

Answer:

C. -7

Step-by-step explanation:

See the picture for steps :)

6 0
2 years ago
6f-7=29;5 what is this answer or how do you do i am having trouble finding it out
erik [133]
6(5)-7
30-7
23
The answer is false because it doest equal 29
8 0
3 years ago
Read 2 more answers
Georgina knows the inequality is true, but she cannot remember what number is in the denominator.
stealth61 [152]

Answer:

<h3>D. 12</h3>

Step-by-step explanation:

Which number could be the missing number?

Given the inequality expression, 1/10 > 1/ ?

We are to fine the missing number that will make the inequality true;

Cross multiply:

1 * x > 1*10

x > 10

Hence the value of x greater than 10 is the answer. From the options, the only value greater than 10 is 12. Hence 12 is the correct answer.

8 0
3 years ago
Read 2 more answers
(10000*C)/1.05+(10000*C)/1.05^2…..(10000*C)/1.05^13=100<br> Find C?
rosijanka [135]

9514 1404 393

Answer:

  C ≈ 0.00106455765168

Step-by-step explanation:

This is the sum of 13 terms of the geometric series that has 10000C/1.05 as the first term and a common ratio of 1/1.05. The sum S is given by ...

  S = a1(1 -r^n)/(1 -r) . . . . a1 is the first term, r is the common ratio

Using the known values, we have ...

  100 = (10000C/1.05)(1 -1.05^-13)/(1 -1/1.05))

  0.01 = C(1 -1.05^-13)/0.05

  C = 0.0005/(1 -1.05^-13) ≈ 0.0005/0.469679

  C ≈ 0.00106455765168

3 0
3 years ago
Consider the line which passes through the point P(−1,-3,5), and which is parallel to the line x=1+7t, y=2+2t, z=3+4t Find the p
bija089 [108]

The given line is parameterized by

x(t) = 1 + 7t

y(t) = 2 + 2t

z(t) = 3 + 4t

and points in the same direction as the vector

d/dt (x(t), y(t), z(t)) = (7, 2, 4)

So, the line we want has parameteric equations

x(t) = -1 + 7t

y(t) = -3 + 2t

z(t) = 5 + 4t

Solve for t when one of x, y, or z is equal to 0 - this will tell you for which value of t the line cross a given plane. Then determine the other coordinates of these intersections.

• x = 0, which corresponds to the y-z plane:

0 = -1 + 7t   ⇒   7t = 1   ⇒   t = 1/7

y(1/7) = -3 + 2/7 = -19/7

z(1/7) = 5 + 4/7 = 39/7

⇒   intersection = (0, -19/7, 39/7)

• y = 0 (x-z plane):

0 = -3 + 2t   ⇒   2t = 3   ⇒   t = 3/2

x(3/2) = -1 + 21/2 = 19/2

z(3/2) = 5 + 12/2 = 11

⇒   intersection = (19/2, 0, 11)

• z = 0 (x-y plane):

0 = 5 + 4t   ⇒   4t = -5   ⇒   t = -5/4

x(-5/4) = -1 - 35/4 = -39/4

y(-5/4) = -3 - 10/4 = -11/2

⇒   intersection = (-39/4, -11/2, 0)

8 0
2 years ago
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