Answer:
The answer is D
Step-by-step explanation:
Plug any x value for the y values of f(x) and g(x)
Let's do 0 since it is easier.
f(x)=-2(0)-4=-4
g(x)=-2(0)+2=2
So, g(x) is 6 greater than f(x).
Thus, g is most likely moved 6 units up from f.
Graph the 2 functions on Desmos for a better picture.
Answer:
2y - 6
Step-by-step explanation:
5y - 3(y + 2)
distribute
5y + (-3 * y) + (-3 * 2)
simplify
5y -3y + ( -3 * 2)
5y - 3y + ( -6)
5y - 3y - 6
combine like terms
5-3 = 2
2y - 6
1. The answer is two because if you factor what you can from the equation and then simplify, you are left with 2v+16=(v+8)(?), and by looking at it, the correct answer is two, or A. Review your work, make sure to check your answers before submitting
2. Since two simple factors of 8 are 4 and 2, and they add up to 6, the correct answer is (x+4)(x+2), or B
3. Again, two simple factors of 12 are -4 and -3, so the correct answer is (x-3)(x-4), or D
4. Basically, just factor the quadratic trinomial g^2-2g-24, which turns out to (G+4)(g-6), which is B
Answer: Our required values would be -10x+5, 2x+5 and -25.
Step-by-step explanation:
Since we have given that
g(x) = -4x+5
and
h(x) = 6x
We need to find (g-h)(x) and (g+h)(x).
So, (g-h)(x) is given by
and (g+h)(x) is given by
and (g-h)(3) is given by
Hence, our required values would be -10x+5, 2x+5 and -25.
Answer:
The number of horses that can eat 4 stacks of hay in 8 days = 56 horses
Step-by-step explanation:
The given parameters are;
The time it takes 16 horses to eat 5 stacks = 35 days
Therefore;
The time it takes 16 horses to eat 5/5 stacks (1 stack) = 35 days/5 = 7 days
The time it takes 16 horses to eat 1 stack of hay = 7 days
The time it takes 16 horses/16 to eat 1 stack of hay = 7 days × 16 = 112 days
Therefore;
The time it takes 1 horse to eat 1 stack of hay = 112 days
The time it takes 1 horse to eat 4 × 1 stack of hay = 112 days × 4 = 448 days
The time it takes 1 horse to eat 4 stacks of hay = 448 days
Therefore, given that (448 days)/(8 days/horse) = 56 horse, we have;
The number of horses that will eat 4 stacks of hay in 8 days = 56 horses.
