Answer:
0.9 square units
Step-by-step explanation:
We assume you intend the vertices of the square to be (±√2, 0) and (0, ±√2). Then the diagonals of the square are 2√2 in length and its area is ...
(1/2)(2√2)² = 4
The radius of the inscribed circle is 1, so its area is ...
π·1² = π
and the area outside the circle, but inside the square is the difference of these areas:
area of interest = 4 - π ≈ 0.858407
area of interest ≈ 0.9
Step-by-step explanation:
A transformation may be defined as taking a basic function and then changing it slightly with the predetermined methods. This changes will cause the required graph of that function to shift, move or stretch, which depends on the type of the transformation.
For example:
Let a function be :
For any constants m and n, the function shifts the parent function.
- vertically n units and in same direction of the sign of n.
- horizontally m units and towards the opposite direction of the sign of m.
- The y-intercept becomes ()
- The horizontal asymptote becomes y = n.
- the reflection about x -axis becomes