Circumference of a circle with a radius of 5 inches

Mathematics

2 answers:

Fudgin [204]3 years ago

8 0

Circumference of a circle with a radius of 5 inches is 31.42 in.
You can express that by writing C <span>≈ 31.42 in.
I hope you find this answer the most helpful.</span>

Lerok [7]3 years ago

7 0

Answer is provided in the image attached.

You might be interested in

The scale from a garden to this drawing is 8 ft to 1 cm. the scale from the same garden to another drawing is 2 ft to 1 cm. what

garik1379 [7]

The lengths of the base and height of the garden in the other scale drawing are 0.6 cm and 0.9 cm. So, option A is correct.

What is the scale factor?

The scale factor is calculated by Scale factor = Length of the new drawing ÷ length of the original drawing

Calculation:

It is given that,

For the given triangle drawing, the scale from a garden to this drawing is 8 ft to 1 cm. The scale from the same garden to another drawing is 2 ft to 1 cm.

So, we can compute the scale factors as

8 ft to 1 cm = 1/8 cm

2 ft to 1 cm = 1/2 cm

Then the scale factor for the required lengths is 1/8 ÷ 1/2 = 1/4 cm

Thus, the required lengths are:

The base of the garden on the other scale drawing is

= 2.4 cm × 1/4

= 0.6 cm

The height of the garden on the other scale drawing is

= 3.6 cm × 1/4

= 0.9 cm

Therefore, the lengths of the base and the garden on the other scale drawing are 0.6 cm and 0.9 cm. So, option A is correct.

The given question in the portal was incomplete. Here is the complete question.

Question: The scale from a garden to this drawing is 8 ft to 1 cm. The scale from the same garden to another drawing is 2 ft to 1 cm. What are the lengths of the base and height of the garden in the other scale drawing?

A) 0.6 cm and 0.9 cm

B) 1.2 cm and 1.8 cm

C) 4.8 cm and 7.2 cm

D) 9.6 cm and 14.4 cm

Learn more about scale factors here brainly.com/question/28307342

#SPJ4

5 0

2 years ago

Find the smallest positive $n$ such that \begin{align*} n &\equiv 3 \pmod{4}, \\ n &\equiv 2 \pmod{5}, \\ n &\equiv

Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number $x$ such that taking it mod 4, 5, and 7 leaves the desired remainders: