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max2010maxim [7]
3 years ago
14

Solve the system by using a matrix equation 3x-5y=3 3x-4y=3

Mathematics
2 answers:
natka813 [3]3 years ago
6 0

Answer: B. (1,0)

Step-by-step explanation:

1. We will use the matrix method to solve this problem.

3 -5 3

3 -4 3

2. Apply to Row2 : Row2 - Row1.

3 -5 3

0 1 0

3. Simplify rows.

3 -5 3

0 1 0

Note: The matrix is now in row echelon form.

The steps below are for back substitution.

4. Apply to Row1 : Row1 + 5 Row2.

3 0 3

0 1 0

5. Simplify rows.

1 0 1

0 1 0

Note: The matrix is now in reduced row echelon form.

6. Therefore,

x=1

y=0

or (1,0).

babunello [35]3 years ago
3 0

Answer:

The correct answer is B. (1,0).

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At the gym, Jasper was able to bench press 224 pounds, which was 7/8 of the weight that Balin was able to bench press. Which sho
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Answer:

The answer SHOULD be 7/8=224/x;256 pounds.

You may have made a mistake in inputting it here on Brainly. So look for the one that matches that.

Step-by-step explanation:

This is what we know:

Jasper = 224 pounds

Balin = x

Jasper = 7/8 of x

Now we make an equation for that:

(\dfrac{7}{8})(x) = 224pounds

To match the selections we will isolate 7/8 on one side of the equation:

\dfrac{7}{8}=\dfrac{224}{x}

Using ratio and proportion we can solve for what x is. Multiply 224 by 8 and divide it by 7. Or you can do it this way too:

\dfrac{7}{8}=\dfrac{224}{x}

(7)(x)=(224pounds)(8)

7x=1792pounds

x=\dfrac{1792pounds}{7}=256pounds

So x = 256 pounds

7 0
3 years ago
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Help. me math 20 points​
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3 years ago
Pls help asap! It’s due in one hour!!
AfilCa [17]
1. t = 7
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In a laboratory, scientist are performing chemical reactions.the amount of product formed by a reaction can be determined by equ
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Answer:

  0.25

Step-by-step explanation:

The only constant in the equation is called the "constant of proportionality." Its value is 0.25.

The constant of proportionality is 0.25.

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3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
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