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MArishka [77]
3 years ago
13

Find the value of the variable. Then find the angle measures of the polygon.

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
7 0
First set up the equation (sum of the angles is 180)

2x + 2(x-1) + (5x +2) = 180

distribute:
2x + 2x -2 + 5x +2 = 180

combine like terms:
9x = 180
solve for x:

x = 20

SO:

2x° = 2(20) = 40 degrees
2(x-1)° = 2(20) - 2 = 40 - 2 = 38 degrees
5x + 2°= 5(20) + 2 = 100 + 2=102 degrees

check: 40 + 38 + 102 = 180
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Area of the figure: A)128 B)136 C)153 C)258
GarryVolchara [31]

Answer: 153

Step-by-step explanation:

area of rectangle= 16 x 3= 48

area of trapezium= 1/2(a+b)h

=1/2(16+5)x 10

=105

105+48= <u>153 in^2</u>

3 0
3 years ago
Angie divides the polynomial function f(x)=x3+3x2−7x−21 by (x + 3). What can she conclude from the fact that the remainder is eq
iren [92.7K]

Answer:

See below

Step-by-step explanation:

<u>Given function</u>

  • f(x)=x³ + 3x²- 7x - 21

<u>We can find its factors:</u>

  • x³ + 3x² - 7x - 21 =
  • x²(x + 3) - 7(x + 3) =
  • (x² - 7)(x + 3)

We can conclude that the given polynomial function is fully divisible by (x + 3) and the quotient is (x² - 7)

Also one of zeros of the function is -3

8 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
What is the greatest common factor of (8x-6)
bija089 [108]

Answer:

Step-by-step explanation:

(8x-6)

=2(4x-3)

5 0
3 years ago
What is the difference between constructing and drawing geometric figures? Give a real-world example of each.
Furkat [3]
<span>The difference between constructing and drawing geometric figures:
</span>Drawing Geometric Figures refers to drafting, in which you are trying to create or sketch geometric figures using ruler, paper, etc.
While constructing geometric figure  refers to constructing or building a geometric figure with the use of compass, graph paper, etc.
8 0
3 years ago
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