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Serga [27]
3 years ago
9

We are planning an experiment comparing three fertilizers. We will haveExercise 7.2 six experimental units per fertilizer and wi

ll do our test at the 5% level. One of the fertilizers is the standard and the other two are new; the standard fertilizer has an average yield of 10, and we would like to be able to detect the situation when the new fertilizers have average yield 11 each. We expect the error variance to be about 4. What sample size would we need if we want power .9

Mathematics
1 answer:
nignag [31]3 years ago
4 0

Answer:

The required sample size is 42.

Step-by-step explanation:

Please see the attached picture for the complete answer.

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I WILL MARK BRAINLIEST
Korvikt [17]

Answer:

I believe the answer is A. 15-(3xy)

Step-by-step explanation:

The expression you are given is 15-(yx3) and option A is 15-(3xy). All they did was flip the values in the parentheses. It doesen't matter what value is first because the negative sign will be distributed to everything in the parentheses.

Hope this helps!!

Mark me brainliest please!

8 0
2 years ago
The distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on y
kaheart [24]

Answer:

d(1) = -3 and d(2)= -28

Step-by-step explanation:

Given that the distance d, in centimeters, that a diving board bends below its resting position when you stand at its end is dependent on your distance x, in meters, from the stabilized point

d(x)=-4x^3+x^2

For finding out the distances for x=1 and x=2

let us substitute 1 and 2 for x

d(1) = -4(1^3)+1^2 = -3

d(2) = -4(2^3)+2^2 \\= -28

d(1) = -3 and d(2)= -28

3 0
3 years ago
The length of a rectangle is 7 centimeters greater than the width.
Lisa [10]

Answer:

length = 17cm, width = 10cm

Step-by-step explanation:

2L + 2w = 54

L = w + 7

Substitute:

2(w + 7) + 2w = 54

2w + 14 + 2w = 54

4w = 40

w = 10

L = 10 + 7 = 17

7 0
3 years ago
Someone please help. Thank u so much
Nonamiya [84]
1. $120.66+15.55=$136.21
2. $700.00-$136.21=?
3. The answer is in the 1st and 2nd question
7 0
3 years ago
The differential equation in Example 3 of Section 2.1 is a well-known population model. Suppose the DE is changed to dP dt = P(a
LuckyWell [14K]

Answer:

Decreases

Step-by-step explanation:

We need to determine the integral of the DE;

dP/dt=P(aP-b)

dP=P(aP-b)dt

1/(dP^2-bP)dP=dt

We can solve this by integration by parts on the left side. We expand the fraction 1/P²:

1/(d-b/P)\cdot{P^2} dP

let

u=d-b/P

du/dP=b/P^2

dP=\int\limits {P^2/b} \, du

P=lnu/b

Substitute u in:

P=ln(d-b/P)/b

Therefore the equation is:

ln(d-b/P)/b=t

We simplify:

d-b/P=e^b^t

P=b/(d-e^b^t)

As t increases to infinity P will decrease

6 0
3 years ago
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