All categories

3 years ago

Factor completely 12x4 + 6x3 + 18x2.

Mathematics

1 answer:

Semmy [17]3 years ago

8 0

Answer:

B)3x^2 (4*x^2 + 2x + 6)

Step-by-step explanation:

Step 1: Find the Greatest common factor of the given expression.

12x^4 + 6x^3 + 18x^2

The above expression can be written as .

= 2*2*3*x^4 + 2*3*x^3 + 2*3*3*x^2

Here 3x^2 is prime factor

Step 2: Let's take out the 3 $x^{2}$ and write the remaining terms in the parenthesis.

= 3x^2 (2*2*x^2 + 2x + 2*3)

= 3x^2 (4x^2 + 2x + 6)

Therefore, the answer is B)3x^2 (4*x^2 + 2x + 6)

Thank you.

You might be interested in

Select the correct answer What is the solution for in the equation? 4+ 5x-7 = 10+ 3x-2 * Y Lee R=###

Lina20 [59]

Answer:

x=11/2

Step-by-step explanation:

4+5x‒7=10+3x‒2

5x‒3=8+3x

5x‒3x=8+3

2x=11

2x/2=11/2

x=11/2

7 0

3 years ago

A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is

katovenus [111]

Answer:

The constant of variation is 4032

Step-by-step explanation:

Given:

Let a rectangle (say A) has length of rectangle(l)= 72 cm and width of rectangle(w) = 56 cm.

Area of rectangle is multiply its length by its width.

Then,

area of rectangle (A) = $l \times w$ = $72 \times 56$ = 4,032 square cm.

It is given that the other rectangle B has the same area as the rectangle A.

Then, the area of rectangle (B) = area of rectangle (A) = 4,032 square cm. .......[1]

First find the length of rectangle B:

Given: width of the rectangle B is 21 cm

then, by definition

Area of rectangle B = $l \times w$ = $l \times 21$

From [1];

4032 = $l \times 21$

Divide 21 both sides we get;

$l =\frac{4032}{21} = 192$ cm

therefore, the length of rectangle B is 192 cm

To find the constant variation:

if y varies inversely as x

i.e, $y \propto \frac{1}{x}$

⇒ $y = \frac{k}{x}$ where k is the constant variation.

or k = xy

As area of rectangle is multiply its length by width.

This is the inversely variation.

as: $l \propto \frac{1}{w}$

or $l = \frac{A}{w}$ where A is the constant of variation

Since, the area (A) of both the rectangles are constant.

therefore, the constant of variation is, 4032

5 0

3 years ago

Daniela and Jack are hiking a steady incline. They use their GPS device to determine their elevation every 15 minutes. At 15 min

kow [346]

Answer:

$h=40t+9700$

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, $t_1=15$ min, the elevation, $h_1= 10,300$ feet and

at the time $t_2= 30$ min, the elevation, $h_2=10,900$ feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let $h$ be the elevation at any time instant $t$ , so the linear relation among these quantities is

$h=mt+C_0\;\cdots(i)$

where $m$ is the rate of change of elevation with respect to time and $C_0$ is constant.

The change in the elevation, $\Delta h=h_2-h_1= 10,900-10,300=600$ feet.

and the change in time, $\Delta t=t_2-1_1=30-15=15$ min.

So, change in the elevation in unit time,

$m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40$ feet/min.

Now, from equation (i)

$h=40t+C_0$

As the elevation, $h=h_1$ at time $t=t_1$ , so

$10,300=40\times15+C_0$

$\Rightarrow C_0=9700$

Hence, the required equation is

$h=40t+9700$

where the elevation, $h$ , is in feet and time, $t$ , is in minutes.

3 0

2 years ago

Help!!!!!!!!!!!!!!!!!!!!!

Stells [14]

your answer is B. I believe im not 100% sure though.

7 0

2 years ago

The augmented matrix of a system of equations has been transformed to an equivalent matrix inâ€‹ row-echelon form. Usingâ€‹ x, y

jenyasd209 [6]

Answer: The system of equations is:

x + 2y + 2 = 4

y - 3z = 9

z = - 2

The solution is: x = -22; y = 15; z = -2;

Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.

The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a Row Echelon Form, which satisfies the following conditions:

There is a row of all zeros at the bottom of the matrix;
The first non-zero element of any row is 1, which called leading role;
The leading row of the first row is to the right of the leading role of the previous row;

For this question, the matrix is a Row Echelon Form and is written as:

$\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]$ $\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]$

or in system form:

x + 2y + 2z = 4

y + 3z = 9

z = -2

Now, to determine the variables:

z = -2

y + 3(-2) = 9

y = 15

x + 30 - 4 = 4

x = - 22

The solution is (-22,15,-2).

4 0

3 years ago