Answer:
a) v = 12.21m/s
a = 4.07 m/s²
b)v = 11.24m/s
a = 3.75 m/s²
Step-by-step explanation:
a) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 100
s₀ = x
v = v
t = 9.69 - 3 = 6.69s
s = s₀ + vt
100 = x + v*6.69
100 = x + 6.69v
As x = 3v/2
100 = 3v/2 + 6.69v
100 = 1.5v + 6.69v
100 = 8.19v
v = 12.21m/s
a = v/3 = 4.07 m/s²
b) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 200
s₀ = x
v = v
t = 19.30 - 3 = 16.30s
s = s₀ + vt
200 = x + v*16.3
100 = x + 16.3v
As x = 3v/2
200 = 3v/2 + 16.3v
200 = 1.5v + 16.3v
200 = 17.8v
v = 11.24m/s
a = v/3 = 3.75 m/s²
Answer: 10x + 50
Step-by-step explanation:
lets say that x is equal to the amount of weeks that she runs. She starts off the first week with 50
Then, since she is adding 10 every week, you would do 10x, or 10 times the amount of weeks that she runs.
Since you originally started with 50, you have to add the 50 to the 10x.
So you get...
<h3>
10x + 50</h3>
For example
on week 2, if you plug in 2 to x you get
10(2) +50
20 + 50
70 laps after the second week
Original Question:
100 - [(25/5) x 10] = ?
Note: Always answer what's inside FIRST. In this case, the main ts the brackets, but there's also parenthesis in it too. So solve that.
→100 - [(5) x 10] = ?
Now, solve what's inside the brackets.
→100 - [50] = ?
Well, you can get rid of the brackets.
→100 - 50 = ?
Subtract!
→100 - 50 = 50
Solution:
50
