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laila [671]
3 years ago
8

The height and base radius of a cone are increased by a factor of 2 to create a similar cone. How is the slant height of the con

e affected? The slant height of the larger cone is equal to the slant height of the smaller cone. The slant height of the larger cone is double the slant height of the smaller cone. The slant height of the larger cone is 4 times the slant height of the smaller cone. The slant height of the larger cone is 8 times the slant height of the smaller cone.
Mathematics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

The slant height of the cone affected is two times the slant height of original cone

Step-by-step explanation:

we know that

If the height and base radius of a cone are increased by a factor of  to create a similar cone

then

the scale factor is equal to  

therefore

the slant height of the cone affected is equal to the slant height of the original cone multiplied by the scale factor

Find the slant height of the original cone

Let

l-----> slant height of original cone

la-----> slant height of the cone affected

Applying the Pythagoras theorem

so

The slant height of the cone affected is two times the slant height of original cone

(I GOT THIS FROM SOMEONE ELSES ANSWER IN 2017 SO I HOPE THIS HELPS)

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Bas_tet [7]
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4 0
3 years ago
Which type of parent function is f(x) =^3cubed x
sergij07 [2.7K]

Answer:

Cube Root

Step-by-step explanation:

Because there is a 3 outside the symbol.

That means the equation is stating: y * y * y = x

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7 0
2 years ago
Someone please help me out with these questions . I don’t get them at all.
iVinArrow [24]

Answer:

a)similar; b)similar; c)similar; d)NOT similar

Step-by-step explanation:

>In general if

all corresponding angels are ≅, and

all corresponding sides are in proportion

then the Δs are similar

>we have 3 similarity theorems AA, SSS, and SAS

a)

we can use that sum of angles in a triangle is 180 to find the missing angles

180-96-32 = 52

so in the smaller triangle the angles are 96°-52°-32°

in the larger triangle the angles given are 52°-32°

Since there are 2 corresponding angles congruent, AA theorem of similarity says that the 2 triangles are similar. The transformations were that the big triangle was shrunk and rotated

b)

here we are given a pair of congruent angles and we need to check if the sides are in proportion, is 14/44.8 equal to 20/64?

14/44.8 =.3125 is equal to 20/64=.3125

since we have two corresponding sides in proportion and the angles in between them congruent the SAS theorem says that the 2 triangles are similar. The transformation was that the small triangle was dilated.

c)

because we are given the 2 angles are congruent we can conclude that the lines NH and SL are parallel. NH║SL let us conclude that ∡H and ∡ L are congruent because 2 parallel lines cut by a transversal (ML in our case) form congruent angles. So ΔMNH  is similar to ΔMSL because of AA theorem of similarity (one pair of A was given congruent, one other pair of A we concluded was congruent)

d)

here we have to check if all the sides are in proportion to see if SSS theorem of similarity applies here

18/90 = .2

44/202.4≈.22

58.5/211.2≈.28

.2≠ .22 ≠ .28

since the sides are not in proportion the 2 triangles are NOT similar.

4 0
3 years ago
I need help on numbers 17&18.
jekas [21]
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5 0
3 years ago
Read 2 more answers
Help me with question a please ! With full workings !
frosja888 [35]
A)


\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
%  (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)


c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
%   (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}

\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
7 0
3 years ago
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