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Sonja [21]
2 years ago
15

What makes 50.652 rational?

Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0
Remember a rational number is a number that can be written with two whole numbers in a fraction, for example, 0.25 can be written as 1/4 notice how, both, the numerator and denominator are whole numbers AKA Integers(numbers that aren't decimals or fractions).

any number that can't be written by whole numbers in the numerator or denominator is an irrational number, things like Pi, Pi cannot be written by two whole numbers in the fraction. 

50.652, is definitely rational because the fraction does not need decimal numbers in the numerator or denominator.

it can be written as:
50 \frac{50}{50} or \frac{12663}{250}

notice how neither the numerator or denominators are decimals?


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Needing this for tomorrow thanks help me please is hurry
Alisiya [41]

39) 6 *15 = 90 in deposits

40) 5 + 10 + 15 = 30 withdrew

41) 35 +90 = 125 - 30 = 95 in the account

3 0
3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
A roadside vegetable stand sells pumpkins for $5 each and tomatoes for $3 each. The
stealth61 [152]

Answer:

Step-by-step explanation: I need help

3 0
2 years ago
I’m having trouble on 10-11, if you can find the answer. Thank you!
PolarNik [594]

Answer:

10-11 is -1

Step-by-step explanation:

i don'T care much for attachments ;)

3 0
2 years ago
-7^-2<br>does anyone know ?
Leno4ka [110]

Negative exponents mean that you flip the number upside down

so -7^-2 would become 1/-7^2

-7^2 would be 49

so the answer is <em>1/49</em>

8 0
2 years ago
Read 2 more answers
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