Answer:
Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
Please give brainliest
21000 people paid for general admission and 6000 paid for reserved seats. This is solved by making 2 equations. Out of 27000 people who were at game, x of them paid for general admission and y for reserved seats, thus
x + y = 27000
As said, daily receipts were 204000$. As reserved seat is 13$, y of them gave 13$ each (y*13$) and x of them gave 6 for general admission(x*6) and those two add up and we get second equation
13y + 6x = 204000.
This can be solved by transforming first equation into x = 27000 - y and then replacing the x in second.
13y + 6*(27000 - y) = 204000
13y + 162000 - 6y = 204000
7y = 42000
y = 6000
x + 6000 = 27000
x = 27000 - 6000 = 21000
So than given that the diameter of a circle is 28 inches so from this result the radius is d/2 = 28/2 = 14 inches
than the circumference of circle will be equal 2*3,14*14 = 6,28 *14 = 87,92 so rounded equal 88 in.
so this mean that choice c.) is right sure
hope this will help you
Answer:
x = 15
Step-by-step explanation:
Use pythagorean theorem: 

Step-by-step explanation:
we have
length =8in
breadth =6in
since . The length and width of the actual flower bed will be 24 times larger than the length and width in the drawing.
new
length=8×24=192in
breadth =6×24=144in
(b) What is the perimeter of the actual flower bed ? Show your work.
<em>answer:the perimeter of the</em><em> </em><em>actual flower bed</em><em> =2(l+b)</em>
<em> =2(l+b)=2(192+144)=672</em><em>in</em>
(a) What is the perimeter of the drawing? Show your work
<em>answer</em><em> </em><em>:</em><em> </em><em>the perimeter of the </em><em>drawing</em>
<em>=</em><em>2</em><em>(</em><em>8</em><em>+</em><em>6</em><em>)</em><em>=</em><em>9</em><em>6</em><em>in</em>
<em>(c) What is the effect on the perimeter of the flower bed with the dimensions are multiplied by 24? Show your work</em>
<em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>flower </em><em>bed</em><em> </em><em>/</em><em>p</em><em>e</em><em>r</em><em>i</em><em>m</em><em>e</em><em>t</em><em>e</em><em>r</em><em> </em><em>o</em><em>f</em><em> </em><em>d</em><em>r</em><em>a</em><em>w</em><em>i</em><em>n</em><em>g</em>
<em>=</em><em>9</em><em>6</em><em>/</em><em>6</em><em>7</em><em>2</em><em>=</em><em>1</em><em>/</em><em>7</em>
<h3>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>drawing</em><em> </em><em>is</em><em> </em><em>increased</em><em> </em><em>by</em><em> </em><em>7</em><em>t</em><em>i</em><em>m</em><em>e</em><em>s</em><em> </em><em>of</em><em> </em><em>perimeter</em><em> </em><em>of</em><em> </em><em>flower</em><em> </em><em>bed</em></h3>