The answer for that problem is X<26
Answer:B
Step-by-step explanation: Alternate exterior angles theorem
Answer:
2x^2 + 2y^2 + 2z^2
Step-by-step explanation:
x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
First step is to put all the same ones together
( FYI, xy and yx is the same thing, just like how
2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes
(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +
(z^2 +z^2) + (zx - zx)
2x^2 + 2y^2 + 2z^2
All the others just cancel themselves out, for example, xy-xy
When anything minus themselves it will become 0
<em>Question 5</em>
Vertical angles are <u>congruent</u>. Therefore, 
. The sum of two supplementary angles equals 
.
Therefore, 
<em>Question 6</em>
<em>Question 7</em>
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<em>Question 8</em>
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