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murzikaleks [220]
3 years ago
7

The diameter of a circle is 5 ft. Find the circumference TO THE NEAREST TENTH

Mathematics
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:

15.7

Step-by-step explanation:

3.14(5)

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jeyben [28]

Answer:

its B

Step-by-step explanation:

7 0
3 years ago
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Help please i suck at this
kap26 [50]

Answer:

Mistake: -3-5=-2, -3-5=-8

Step-by-step explanation:

-3-(7x+5)+9x=-8+3x+10

-3-7x-5+9x=4x+2

-8+2x=4x+2

-8-2=4x-2x

-10=2x

-10/2=x

-5=x

5 0
3 years ago
Josiah bought 22 chicken wings for $26.40. How much would it cost for 9 wings?
cricket20 [7]

Answer:

it would cost $10.8 for 9 chicken wings.

Step-by-step explanation:

Cost of 22 chicken wings = $26.40

we have to find first, cost of 1 chicken wings

For that we divide both side by 22

cost of 22/22 chicken wings = $26.40/22 = 1.2

Thus, cost of 1 chicken wings = $1.2

to fins cost of 9 chicken wings

we multiply both sides by 9

cost of 1*9 chicken wings = $1.2*9

cost of 9 chicken wings = $10.8

Thus, it would cost $10.8 for 9 chicken wings.

7 0
3 years ago
An investment fund starts at $0 and grows at a rate of $100 per month. Another fund starts at $4000 and reduces by $720 per year
Pie

Answer:  2 years 1 month

Step-by-step explanation:

2 years 1 month at $100 a month = $2,500

$720 x 2 years = $1,440

$720 / 12 months = $60

$1,440 + $60 = $1,500

$4,000 - $1,500 = $2,500

6 0
3 years ago
Sin2x-sin2xcos2x=sin4x
yaroslaw [1]

It looks like the given equation is

sin(2x) - sin(2x) cos(2x) = sin(4x)

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

sin(2x) - 3 sin(2x) cos(2x) = 0

sin(2x) (1 - 3 cos(2x)) = 0

Then we have two families of solutions,

sin(2x) = 0   or   1 - 3 cos(2x) = 0

sin(2x) = 0   or   cos(2x) = 1/3

[2x = arcsin(0) + 2nπ   or   2x = π - arcsin(0) + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

[x = nπ   or   x = π/2 + nπ]

… … …   or   [x = 1/2 arccos(1/3) + nπ   or   x = -1/2 arccos(1/3) + nπ]

7 0
3 years ago
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