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3 years ago

9

Picture above 9th grade math (please include properties and steps) will mark brainly thank you!

1 answer:

Nezavi [6.7K]3 years ago

5 0

Answer:

Adition property of equality and subtraction [reperty of equality.

Step-by-step explanation:

You might be interested in

1) How much money will you have in an account after 5 years if you invest $1,200 at 2.5%

Leya [2.2K]

Answer:

$ 1,350

Step-by-step explanation:

i = (prt) / 100

p = $ 1,200 r = 2.5% t = 5 years

i = (1,200 x 2.5 x 5) / 100

i = $ 150

amount = p + i

= 150 + 1,200

= $ 1,350

8 0

2 years ago

Q1.The cost of $16.50 for the music was reduction of 12% on the original cost.

NNADVOKAT [17]

Q1) £16.50 x 1.12 = £18.48
Q2)

2+9+1= 12
3h 33m = 213m
213/12 = 17.75
2x17.75 = 35.5 (music)
9x17.75 = 159.75 (films)
1x17.75 = 17.75 (books)

So it’s 159.75 minutes for the films to download

7 0

3 years ago

Graph the equation y-1=-3(x-3)

trapecia [35]

Answer:

y= -3x +10

the y-intercept is at 10 and then go 3 down one to the right

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Jill works on the weekends. Last saturday, she worked 5.75 hours. Sunday she worked 6.75 hours. she earn $7.50 per hours. How mu

leva [86]

93.75 because 5.75x7.50=43.125 and 6.75x7.50=50.625 and 50.625+43.125=93.748 and round it to the near test hundredth because it’s money and that’s 93.75

7 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago