Carbon monoxide<span>, lead, </span>nitrogen dioxide<span>, </span>ozone<span>, particulate matter, and </span>sulfur dioxide
Answer:
4.06 g BaCl₂
Explanation:
Molarity (M) is given by this formula:
We are given M and L in this equation; we can solve for moles of BaCl₂ and use stoichiometry to convert this amount to grams.
First convert 50.0 mL to L:
Plug this value for L and 0.390 for M into the equation.
Solve for mol by multiplying .05 to both sides.
We have .0195 mol BaCl₂. Now let's use stoichiometry to calculate the amount of grams in .0195 mol BaCl₂.
The molar mass of BaCl₂ is 208.23 g so by using stoichiometry...
There are 4.06 g of BaCl₂ in this solution.
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Answer: Explanation:
Gallium has three electrons in the outer energy level and therefore has three valence electrons. The identification of valence electrons is vital because the chemical behavior of an element is determined primarily by the arrangement of the electrons in the valence shell.
Answer:
Mass = 20,000 g
Explanation:
Given data:
Mass of MgO formed = ?
Mass of Mg react = 12 Kg (12 Kg × 1000/1 Kg = 12000 g)
Solution:
Chemical equation:
2Mg + O₂ → 2MgO
Number of moles of Mg:
Number of moles = mass/molar mass
Number of moles = 12000 g/ 24 g/mol
Number of moles = 500 mol
Now we will compare the moles of Mg and MgO.
Mg : MgO
2 : 2
500 : 500
Mass of MgO:
Mass = number of moles × molar mass
Mass = 500 mol × 40 g/mol
Mass = 20,000 g