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jonny [76]
3 years ago
15

According to this chemical equation which molecules represeny the products 4fe+3O->2fe2O3 A iron B iron and oxygen C iron oxi

de D iron oxygen and iron oxygen
Chemistry
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer: C. iron oxide

Explanation:

In a chemical reaction , the reactants are written on the left hand side followed by a rightarrow and then products are given on the right side of the arrow.

In the given chemical equation :

4Fe+3O_2\rightarrow 2Fe_2O_3

Reactants are iron (Fe) and oxygen (O_2) and product is iron oxide (Fe_2O_3).

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Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2H2S(g) 3O2(g)2H2O(l) 2SO2
Marizza181 [45]

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\Delta _rH=-1124.14kJ/mol

Explanation:

Hello!

In this case, since the standard enthalpy change for a chemical reaction is stood for the enthalpy of reaction, for the given reaction:

2H_2S(g) +3O_2(g)\rightarrow 2H_2O(l) +2SO_2(g)

We set up the enthalpy of reaction considering the enthalpy of formation of each species in the reaction at the specified phase and the stoichiometric coefficient:

\Delta _rH=2\Delta _fH_{H_2O,liq}+2\Delta _fH_{SO_2,gas}-2\Delta _fH_{H_2S,gas}-3\Delta _fH_{O_2,gas}

In such a way, by using the NIST database, we find that:

\Delta _fH_{H_2O, liq}=-285.83kJ/mol\\\\\Delta _fH_{SO_2, gas}=-296.84kJ/mol\\\\\Delta _fH_{O_2,gas}=0kJ/mol\\\\\Delta _fH_{H_2S,gas}=-20.50kJ/mol

Thus, we plug in the enthalpies of formation to obtain:

\Delta _rH=2(-285.73kJ/mol)+2(-296.84kJ/mol)-2(-20.50kJ/mol)-3(0kJ/mol)\\\\\Delta _rH=-1124.14kJ/mol

Best regards!

8 0
3 years ago
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