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jonny [76]
3 years ago
15

According to this chemical equation which molecules represeny the products 4fe+3O->2fe2O3 A iron B iron and oxygen C iron oxi

de D iron oxygen and iron oxygen
Chemistry
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer: C. iron oxide

Explanation:

In a chemical reaction , the reactants are written on the left hand side followed by a rightarrow and then products are given on the right side of the arrow.

In the given chemical equation :

4Fe+3O_2\rightarrow 2Fe_2O_3

Reactants are iron (Fe) and oxygen (O_2) and product is iron oxide (Fe_2O_3).

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a 1.00-l solution contains 2.50×10-4 m cu(no3)2 and 1.20×10-3 m ethylenediamine (en). the kf for cu(en)22 is 1.00 × 1020. chegg
Debora [2.8K]

The concentration of copper in the solution is

5.1 \times 10^{18}  \: M.

The volume of the solution = 1.00 L

Moles \: of \:Cu(NO_{3}) _{2} = 2.50 \times 10 {}^{ - 4}

Moles \:  of  \: Ethylenediamine = 1.20 \times 10.3

k _{f} = 1.00 \times 10^{20}

Overall balanced equation of reaction is,

Cu^{2 + }(aq)  \:  + 2en \: (aq)→ Cu(en) ^{2 + }_{2}(aq)

Moles \: of \:Cu(NO_{3}) _{2} =0.00025 \: mol

Mole ratio for,

Moles \: of\:Cu(NO_{3}) _{2}: en

2: 1

Moles \: of \: en = 0.000250 \times 2

= 0.00050 \: moles

Remained moles of en are= (0.00120-0.000500)

= 0.000700 \: moles

The concentration of copper in the solution is,

k_{f} =  \frac{Cu(en)^{2 + }_{2}  }{Cu^{2+}en^{2}  }

1.00 \times 10 ^{20} =  \frac{0.000250}{(Cu )^{2 +}  \times (0.000700)^{2 + } }

=  5.1 \times 10^{18}  \: M.

Therefore, the concentration of copper in the solution is

5.1 \times 10^{18}  \: M.

To know more about molarity, refer to the below link:

brainly.com/question/8732513

#SPJ4

4 0
1 year ago
What is the difference between relative humidity and humidity?
Paul [167]
Relative humidity tells you how much water vapor is in the area. Humidity is like a ratio of absolute humidity and the potential amount of water saturation that may be in an area.
3 0
3 years ago
The amplitude of a wave is
Ghella [55]

Answer:

the answer is A.

Explanation:

I hope this helps have a fantastic day!

4 0
3 years ago
Read 2 more answers
Can someone check that I did this correctly? What does it mean by “networks” and “formula units”?
ale4655 [162]
Idk i just need to ask a question
6 0
3 years ago
28 ml of 0.10 m hcl is added to 60 ml of 0.10 m sr(oh)2. determine the concentration of oh− in the resulting solution.
Blababa [14]
Here is an acid-base reaction. Hydrochloric acid (HCl) reacts with strontium hydroxide [ Sr(OH)2 ]

Ions H+ and OH- neutralize each other. If the amounts are not equal, one of them will be in excess. 
Follow the steps as

1. Find moles of ions: mole= Molarity * Volume (in liter) ; n= M * V OR millimole = Molarity * Volume (in ml) ;
2. Write the equation
3. Find out excess ion
4. Use final volume (V acid + V base ) to calculate concentration of excess ion.

n HCI = 28 ml * 0.10 M = 0.28 mmol, releases 0.28 mmol H+ ions
n Sr(OH)2= 60 ml * 0.10 M= 0.60 mmol, releases 2* 0.60=1.20 mmol OH- ions
since Sr(OH)2⇒ Sr2+ + 2OH-

Neutralization reaction is OH- + H+ ---> H2O. The ratio is 1:1. That means 1 mmol hydroxide ions will neutralize 1 mmol hydrogen ions. Since OH- ions are greater in amount, they will be in excess

n(OH-) - n(H+)= 1.20 - 0.28 = 0.92 mmol OH- ions UNREACTED.

Total volume= V acid + V base= 28 ml + 60 ml = 98 ml

Molarity of OH- ions= mole / Vtotal = 0.92/98= 0.009 M

The answer is 0.009 M.


5 0
3 years ago
Read 2 more answers
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