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jonny [76]
3 years ago
7

In ocean water, salt is a(n) _____. a. solution b. alloy c. solvent d. solute

Chemistry
2 answers:
stepan [7]3 years ago
3 0
The answer is a. solution :)
marusya05 [52]3 years ago
3 0
It is a solvent or solute
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A buffer contains 0.19 mol of propionic acid (C2H5COOH) and 0.26 mol of sodium propionate (C2H5COONa) in 1.20 L. You may want to
Snezhnost [94]

Explanation:

It is known that pK_{a} of propionic acid = 4.87

And, initial concentration of  propionic acid = \frac{0.19}{1.20}

                                                                       = 0.158 M

Concentration of sodium propionate = \frac{0.26}{1.20}[/tex]

                                                             = 0.216 M

Now, in the given situation only propionic acid and sodium propionate are present .

Hence,      pH = pK_{a} + log(\frac{[salt]}{[acid]})

                       = 4.87 + log \frac{0.216}{0.158}

                        = 4.87 + log (1.36)

                        = 5.00

  • Therefore, when 0.02 mol NaOH is added  then,

     Moles of propionic acid = 0.19 - 0.02

                                              = 0.17 mol

Hence, concentration of propionic acid = \frac{0.17}{1.20 L}

                                                                 = 0.14 M

and,      moles of sodium propionic acid = (0.26 + 0.02) mol

                                                                  = 0.28 mol

Hence, concentration of sodium propionic acid will be calculated as follows.

                        \frac{0.28 mol}{1.20 L}

                           = 0.23 M

Therefore, calculate the pH upon addition of 0.02 mol of NaOH as follows.

             pH = pK_{a} + log(\frac{[salt]}{[acid]})

                       = 4.87 + log \frac{0.23}{0.14}

                        = 4.87 + log (1.64)

                        = 5.08

Hence, the pH of the buffer after the addition of 0.02 mol of NaOH is 5.08.

  • Therefore, when 0.02 mol HI is added  then,

     Moles of propionic acid = 0.19 + 0.02

                                              = 0.21 mol

Hence, concentration of propionic acid = \frac{0.21}{1.20 L}

                                                                 = 0.175 M

and,      moles of sodium propionic acid = (0.26 - 0.02) mol

                                                                  = 0.24 mol

Hence, concentration of sodium propionic acid will be calculated as follows.

                        \frac{0.24 mol}{1.20 L}

                           = 0.2 M

Therefore, calculate pH upon addition of 0.02 mol of HI as follows.

             pH = pK_{a} + log(\frac{[salt]}{[acid]})

                       = 4.87 + log \frac{0.2}{0.175}

                        = 4.87 + log (0.114)

                        = 4.98

Hence, the pH of the buffer after the addition of 0.02 mol of HI is 4.98.

7 0
3 years ago
How many grams of ethyl alcohol (C2H5OH) are in a 1500 ml solution which is 1.54M?
Sedbober [7]

Answer:

The answer is 1.54molar mass.

7 0
3 years ago
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put the ions in order from the ion with the fewest oxygen atoms to the ion with the most oxygen atoms.
dezoksy [38]

Answer:

Chloride , hypochlorite, chlorite , chlorate, perchlorate

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Chlorate ClO3-

Chlorite ClO2-

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Explanation:

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2 years ago
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kvasek [131]
The number of moles:
3.16g of KMnO_{4}
1 mole of KMnO_{4}- 158g.
x moles of KMnO_{4}- 3.16g.
x=\frac{1\ mole*3.16g}{158g}=\frac{3.16}{158}=0.02\ mole

The number of moles:
32.33g of K_{2}CrO_{4}
1 mole of K_{2}CrO_{4}- 194g.
x moles of K_{2}CrO_{4}- 32.33g.
x=\frac{1\ mole*32.33g}{194g}=\frac{32.33}{194}=0.17\ mole

The number of moles:
100g of KHCO_{3}
1 mole of KHCO_{3}- 100.1g.
x moles of KHCO_{3}- 100g.
x=\frac{1\ mole*100g}{100.1g}=\frac{100}{100.1}=0.999\ mole


Greetings, 
n00nst00p :)
3 0
3 years ago
Question 24 Multiple Choice Worth 2 points)<br> [BWS.02] Why is science important for society?
gulaghasi [49]

Answer:

Because the scientific knowledge itself helps solve many basic human needs and it also improves how humans live and their standards. For example, without science medications wouldn´t exist and many technological devices we use now-a-days. We´re surrounded by science, we just don´t really notice it.

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3 years ago
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