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Zarrin [17]
3 years ago
6

Choose the correct mechanistic pathway for each of the following questions:

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

Chlorination of a 1° alcohol using Thionyl Chloride - an SN2 process

Alkene formation via POCl3 reaction with a 2º alcohol - an El process

Explanation:

For a primary alcohol, the chlorination occurs by SN2 mechanism. Remember that the order of SN2 mechanism is methyl > primary > secondary > tertiary. This means that a primary alkyl halide will undergo nucleophillic  substitution by SN2 mechanism.

For a secondary alkyl halide, we normally expect that the mechanism will be E2. When we use POCl3 and pyridine, the alkyl halide passes through a carbocation intermediate which is characteristic of an E1 mechanism.

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Give an example of how you could use different reference frames for the same motion.
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6kg of coal (carbon) is burned in air. What mass of carbon dioxide will be produced? (Assume that combustion is complete and ign
Flauer [41]

The mass of carbon dioxide that would be produced will be 22 kg

<h3>Combustion of carbon</h3>

The combustion of carbon in air can be represented by the equation:

C + O2 ---> CO2

The mole ratio of C to O2 to CO2 is 1:1:1.

Mole of 6kg of carbon = mass/molar mass

                                      = 6000/12

                                      = 500 moles

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                                          = 500 x 44.01

                                           = 22,005 g or 22 kg approximately

More on combustion reactions can be found here: brainly.com/question/13649083

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Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g
Tema [17]

<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      ....(1)

Given mass of oxygen = 50 g

Molar mass of oxygen = 32.00 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen}=\frac{50g}{32g/mol}=1.5625mol

For the given chemical equation:

2H_2O\rightarrow 2H_2+O_2

By Stoichiometry of the reaction:

1 mole of oxygen is produced when 2 moles of water is reacted.

So, 1.5625 moles of oxygen is produced when = \frac{2}{1}\times 1.5625=3.125mol of water is reacted.

To calculate the mass of water, we use equation 1:

Moles of water = 3.125 moles

Molar mass of water = 18.01 g/mol

Putting values in equation 1, we get:

3.125mol=\frac{\text{Mass of water}}{18.01g/mol}\\\\\text{Mass of water}=56.28g

Hence, the mass of water that must be reacted is 56.28 grams.

3 0
4 years ago
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