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frozen [14]
4 years ago
11

The sum of twice a number and seven is 13. Find the number.

Mathematics
1 answer:
Furkat [3]4 years ago
3 0

Answer:

<h2>The answer is 3</h2>

Step-by-step explanation:

Let the number be x

The statement

twice a number is written as

2x

The sum of twice a number and seven is written as

2x + 7

The result is 13

So we have

2x + 7 = 13

Subtract 7 from both sides

That's

2x + 7 - 7 = 13 - 7

2x = 6

Divide both sides by 2

That's

\frac{2x}{2}  =  \frac{6}{2}

We have the final answer as

<h2>x = 3</h2>

Hope this helps you

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The amount of kerosene, in thousands of liters, in a tank at the beginning of any day is a random amount Y from which a random a
Tems11 [23]

Find the marginal density for Y by integrating the joint PDF over all possible values of x:

f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\int_0^y2\,\mathrm dx

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Then the density of X conditioned on Y is

f_{X|Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\frac1y

for 0 and undefined elsewhere.

Thus

P(0.25

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5 0
4 years ago
SHOE COLLECTION: Marquise, Bron'Tavious, and JayDarius each have a shoe collection of Nike Air Vapor Max shoes. Marquise has two
Natasha_Volkova [10]

Answer:

(a) The number of shoes that Marquise has is 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has is 35 pairs of shoes

Step-by-step explanation:

The given information are;

The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious

The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15

The total number of pairs of shoes they have all together = 95 pairs of shoes

Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;

The number of shoes that Marquise has = 2 × X

The number of pairs of shoes that JayDarius has = X + 15

The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95

X + X + 15 + 2 × X = 95

4 × X + 15 = 95

4 × X = 95 - 15 = 80

X = 80/4 = 20

∴ X = 20

(a) The number of shoes that Marquise has = 2 × X = 2 × 20 = 40

The number of shoes that Marquise has = 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has = X = 20

The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes

(c) The number of pairs of shoes that JayDarius has = X + 15 = 20 + 15 = 35

The number of pairs of shoes that JayDarius has = 35 pairs of shoes.

5 0
3 years ago
Help please picture attached
Naya [18.7K]

Answer:

-10

Step-by-step explanation:

3/5(b)=-6

Divide -6 by 3/5, you get -30/3.

4 0
3 years ago
PLEASE HELP ASAP!!! 30 PTS + BRAINLIEST FOR RIGHT/BEST ANSWER!!!
san4es73 [151]

Solve for X in the 2nd equation:

x+2z = 0

Subtract 2z from both sides:

x = -2z


Replace x in the first equation with -2z

-2z +y -z = 1

Combine like terms:

-3z +y = 1

Add 3z to both sides:

y = 3z +1


Replace x and y in the 3rd equation:

2(-2z) + 2(3z+1) = 4

-4z + 6z + 2 = 4

2z +2 = 4

2z = 2

z = 1


Now replace z with 1 in the other equations for x and y:

x = -2z = -2(1) = -2

y = 3z +1 = 3(1) +1 = 3+1 = 4


So you have x = -2, y = 4 ans z = 1


The answer would be written as (-2,4,1)

8 0
4 years ago
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