The type of windows I am using is:Windows 8.1
Answer:
# Code in Python
dictionary={'A':1,'B':2,'C':3,'D':4}
other_dictionary={}
for keys in dictionary:
if dictionary[keys]&1==1:
temp=dictionary[keys]*dictionary[keys]-10*10
other_dictionary[keys]=temp
else:
other_dictionary[keys]=dictionary[keys]
print(other_dictionary)
assert other_dictionary
Explanation:
- Initialize a sample example dictionary and other_dictionary.
- Do a binary comparision for checking odd number
.
- Update the the value stored in the dictionary to store the squared difference of the original value and '10'.
- For even: store the original value (from dictionary).
Answer:
can run at either full- or half-duplex
Explanation:
In Computer Networking, 100Base-T also known as fast ethernet is an ethernet standard that operates at 100Mbps and can run at either full- or half-duplex.
It uses Shielded Twisted Pair (STP) cabling system.
The Variations of 100BaseT are;
- 100BaseTX
- 100BaseFX.
Answer:
b. will be lower if consumers perceive mobile phones to be a necessity.
Explanation:
The price elasticity of demand is described as the percentage variation in the demanded quantity of service or goods divided by the change in the percentage of the price. And henceforth it describes the responsiveness of the demanded quantity to a price change. And now if the mobile phones are thought of as being the necessity then the price will increase as demand will increase, and hence the price elasticity of demand will be lower. And if there is an improvement in the production technology then the price will be lowered, and hence price elasticity of demand will be less as the change in the percentage of the price will be negative. And the exact definition of it as we have described above. Hence, b is correct options.
Answer:
b=0
c=0
lol=list()
while True:
salary=input("Enter your salary: ")
if salary=="e" or salary=="E":
print("Thankyou!!")
break
else:
a=int(salary)
if a>=300000 and a<=400000:
c=c+1
if a<0 or a>400000:
print("Your salary is either too small or too big ")
if a>0 and a<=400000:
a=a-(25/100*a)-(5/100*a)-(2/100*a)
lol.append(a)
b=b+1
if a>=300000:
c=c+1
print(lol)
print("The number of salaries entered is: "+ str(b))
print("The number of salaries that exceeded 300000 is: "+str(c))
