Answer:
The algorithm to find A is even or odd.
- input A.
- Check the remainder on diving by 2 by A%2.
- If remainder is 1 then A is odd Print(Odd).
- If remainder is 0 print(Even).
Explanation:
To check if the number is even or odd we use modulo operator(%).Which gives the remainder on dividing.So if we do this A%2 it will give the remainder that will come out on dividing the value of A by 2.
So if the remainder comes out is 1 then the number is odd and if the remainder is 0 then the number is odd.
Answer:
The answer is "Option B"
Explanation:
Conversion of type is a way of changing an entity from one data type to another. It is used to make the variable process properly by a function in computer coding.
In the C++ language, the result of the multitype value added or any other option is the result between those variables as a large type at that time, that's why choice b is correct.
Answer:
It reverts to the original image
Explanation:
IF function has three parts
IF (condition_to_check , return_if_true , return_if_false)
IF function first checks condition. If it is true it returns first result. Otherwise it returns second result.
Condition to check:
B3>D5
After inserting numbers we get:
10>8
This is correct so the first result will be returned.
The given IF function returns "Closed".
