The width that Mason should set his compass when constructing segment FG is: A. The distance from B to E.
<h3>Width</h3>
FG should be congruent to segment BE. Based on this Mason should set his compass to the width of segment BE when Mason is constructing segment FG.
Hence, the width that Mason should set his compass when constructing segment FG is the distance from B to E which is option is A.
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The equations of the asymptotes of the given hyperbola are; y = ±(40/9)x
<h3>How to Interpret the equation of a hyperbola?</h3>
We are given;
Vertex at (0,−40)
Focus at (0, 41).
Thus, the equation of the asymptote of the given hyperbola is;
y = ±(40/(√41 - (-40))
y = ±(40/(√81)
y = ±40/9
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The volume of the rectangular prism is 3 / 4 inches³
<h3>Volume of a right rectangular prism</h3>
The volume of a right rectangular prism is describe as follows;
where
l = length
w = width
h = height
The rectangular prism is made up of 48 cubes. Each cube has an edge length of 1 / 4 inches.
The volume of the rectangular prism is the sum of the volume of the cubes.
Therefore,
- volume of each cube = (1 / 4)³ = 1 / 64
The cubes are 48 in number. Therefore,
volume of rectangular prism = 1 / 64 × 48 = 48 / 64
volume of rectangular prism = 3 / 4 inches³
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Answer:
4/5 fractions aren't my strong suit but should be eight hopefully
the answers are x = 1/2 and x = -5/3. I hope this helped you, have a great day.