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2 years ago

How to Rewrite 8 + 36 as a product of their GCF and the sum of two factors

Mathematics

1 answer:

siniylev [52]2 years ago

7 0

Answer:

4 (2 + 9)

Step-by-step explanation:

Given expression:

8 + 36

The greatest common factor is the highest number that divides a number:

8 and 36 ;

Factors of 8 : 1,2,4, 8

36 : 1, 2, 3, 4, 9, 18, 36

The highest common factor is 4;

8 + 36 = 4 (2 + 9)

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Using compatible numbers to find each quotient. 18.2 divided by 11

UNO [17]

It is 166 just do some side math if you can and I think youtline get it ok but that's what I got if someone eles gets somthing eles matey listen to them

5 0

2 years ago

Find the perimeter of the figure. Round your answer to the nearest hundredth. in.

Vanyuwa [196]

Answer:

61.13

Step-by-step explanation:

$2\pi(4) = 8\pi = 25.13$

$25.13 + 10 + 10 + 8 + 8 = 61.13$

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3 years ago

Find the measure of the exterior angle.

Illusion [34]

Answer:

108 degrees

Step-by-step explanation:

From the diagram we are given

Interior angles are 2x + 1 and 63 degrees

Exterior angle = 5x -2

The sum of interior angles is equal to the exterior angle

2x + 1 + 63 = 5x - 2

2x + 64 = 5x - 2

2x - 5x = -2-64

-3x = -66

x = -66/-3

x = 22

Get the exterior angle:

Exterior angle = 5x-2

Exterior angle = 5(22) - 2

Exterior angle = 110-2

Exterior angle = 108 degrees

Hence the measure of the exterior angle is 108 degrees

5 0

2 years ago

The Quality Assurance department at a gear company

exis [7]

Answer:
0.6%??

I did 3 divided by 500 and got 0.006 then moved the decimal places to transform the decimal to fraction which ends up being 0.6%

4 0

2 years ago

Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.

zloy xaker [14]

Answer:

$y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

$x={\pi}{4}$

Step-by-step explanation:

We are given that

$y'=\frac{2cos2x}{3+2y}$

y(0)=-1

$\frac{dy}{dx}=\frac{2cos2x}{3+2y}$

$(3+2y)dy=2cos2x dx$

Taking integration on both sides then we get

$\int (3+2y)dy=2\int cos 2xdx$

$3y+y^2=sin2x+C$

Using formula

$\int x^n=\frac{x^{n+1}}{n+1}+C$

$\int cosx dx=sinx$

Substitute x=0 and y=-1

$-3+1=sin0+C$

$-2=C$

$sin0=0$

Substitute the value of C

$y^2+3y=sin2x-2$

$y^2+3y-sin 2x+2=0$

$y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

Hence, the solution $y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

When the solution is maximum then y'=0

$\frac{2cos2x}{3+2y}=0$

$2cos2x=0$

$cos2x=0$

$cos2x=cos\frac{\pi}{2}$

$cos\frac{\pi}{2}=0$

$2x=\frac{\pi}{2}$

$x=\frac{\pi}{4}$

3 0

3 years ago