Solution:
As given Square L M NO is dilated by a scale factor of two about the center of the square to create square L'M'N'O'.
Original line of Dilation = Along P Q
New Dilated line = P'Q'
As scale factor > 1
1. Image Size > Pre image size
2. The two images will be similar.
3. Length of Dilated Line P' Q' = 2 × Length of PQ
As you can see from the diagram drawn below, Dilated line P'Q' will contain the point P and Q.
All four points P,Q,Q',P' are collinear , lie in the same line.
Option (2) dilated line P'Q' will contain the points P and Q is true.
Answer:
The area of the trapezoid is 57.5 square inches
Step-by-step explanation:
we know that
The trapezoid QRST can be divided into a rectangle QRDT and an isosceles right triangle RSD
see the attached figure to better understand the problem
step 1
The area of rectangle is given by the formula
we have
----> altitude
substitute
step 2
Find the area of the isosceles right triangle
The area of triangle is given by the formula
we have
---> because is an isosceles triangle
substitute
step 3
Adds the areas
Answer:
y - 5 = -1(x + 3)
Step-by-step explanation:
Point slope form
y - y1 = m(x - x1) where m = slope and passing through point (x1 , y1)
In this case if the equation in point-slope form contains the point (–3, 5) and has slope –1 then the equation should be:
y - 5 = -1(x - (-3))
y - 5 = -1(x + 3)
Answer:
13 km/hr
Step-by-step explanation:
Speed = (distance covered) / (time to cover the distance)
( 8.45 km) / (0.65 hr)
(8.45 / 0.65) km/hr
He should set up the refreshment stand on the incenter of the obtuse triangle. The incenter of a triangle is described as the intersection between the angle bisectors of a triangle. The inradius are the line segments from the incenter of the triangle to each of the three sides of the triangle which are all equal. The inradius is depicted as the radius of an inscribed circle in the triangle. Therefore, the shortest equal distance from his stand to each road is C. on the incenter.
