Answer:
10n + 28
Step-by-step explanation:
a + d (n-1)
a = 38
d = 10
38 + 10 (n-1)
38 + 10n -10
10n +38 - 10
10n + 28
Hope this helps!
Answer:
dfgsdfgdsfgsd
Step-by-step explanation:
Answer:
i think it's 13/16
Step-by-step explanation:
1/8 times 2 is 2/16 and 3/8 times 2 is 6/16 so add all up to get 13/16
Answer:
i belive it to be A
Step-by-step explanation:
because it does say 6 by 7 by 3 so i would add 3+7 it would give me ten so i belive it to be A. hoped this helped lmk if it did
Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!
We have the point 4,6. 4 is the x, and 6 is the y.
Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.
Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.
So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!
The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²
Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.
So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.
So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²
Solving it out, we first need to work within the parenthesis. Can you solve it?
Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²
8²= 64
9²= 81
64+81 = 145.
So, the distance between point M and point M' would be 145 units
Hope this helps!
If it does not, please let me know so i can try to help!
