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meriva
3 years ago
12

15a) 55 +827of 1+995​

Mathematics
1 answer:
velikii [3]3 years ago
7 0

Answer:

5 5 + 8 27 of 1 + 99 5​= 150

Step-by-step explanation:

Add the expressions.

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Factor completely: (3a+6)^2
zvonat [6]
(3(a+2))^2 factored
4 0
3 years ago
99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest. true or false
tester [92]

The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.

A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.

The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.

In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.

Hence we can generally infer that the given statement is false.

To learn more about confidence intervals visit:

brainly.com/question/24131141

#SPJ4

6 0
2 years ago
(7x – 10) – (–6x – 8).
xeze [42]

Answer:

13x-2

Step-by-step explanation:

1) distribute the negative sign to each term in the second parentheses

(7x-10)-(-6x-8)

7x-10+6x+8

2) combine like terms

7x+6x= 13x

-10+8=-2

13x-2

Hope this helps!

4 0
3 years ago
Please look at the screenshot it has my question.
shepuryov [24]

Answer:

6.25 mins (6 minutes 15 seconds)

Step-by-step explanation:

96 tests = 2mins

300 tests = x mins

X = 2/96 x 300

X = 6.25 mins

3 0
3 years ago
Whoever can answer all these get brainliest please! this is due today!!
OLEGan [10]
#1 is -32
#2 is -11
#3 is -5
#4 is 6
3 0
3 years ago
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