Answer:
1. 88370.45 N/
2. 2500 N.
Explanation:
Pressure, P, is define as the force, F, per unit area, A, applied on/ by an object.
i.e P =
1. The area, A, of the piston of the hydraulic elevator can be determined by;
A =
where r is the radius of the piston.
A = ×
= × 0.09
= 0.2829
Pressure required to lift a truck of 2500 kg mass can be determined as;
P =
F = W = mg
= 2500 × 10
= 25 000 N
So that,
P =
= 88370.45 N/
The pressure required is 88370.45 N/.
2. =
Area of small piston =
= ×
= 0.02829
So that,
=
= 2500 N
The force applied to the small piston is 2500 N.