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Len [333]
3 years ago
13

What is one property of iodine

Physics
1 answer:
mamaluj [8]3 years ago
6 0

Answer: I2

Explanation:

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A planet has been observed orbiting a nearby star. This star has a mass of 3.5 solar masses, and the planet is 4.2 AU from the s
kondaur [170]

Answer:

4.6 years

Explanation:

This is solved using Kepler's third law which says:

T^2=\frac{4\pi ^2}{GM} a^2

Where

T = Orbital period of the planet (in seconds)

a = Distance from the star (in meters)

G = Gravitational constant

M = Mass of the parent star (in kg)

From the information given

M = 3.5M_{sun} = 6.96*10^{30} kg

a=4.2AU = 6.28*10^{11} meters

G = 6.67*10^{-11}m^3kg^{-1}s^{-2}

We put this into Kepler's law and get:

T=\sqrt{\frac{4\pi ^2}{6.67*10^{-11}*6.96*10^{30}} (6.28*10^{11})^3}=145,128,196 seconds.

This when converted to years is 4.6 years.

4 1
3 years ago
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HELP! how did michael jordan influence future basketball players to make prodcuts?
nataly862011 [7]

Answer:

By encouraging them.

Explanation:

#CARRYONLEARNING

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3 years ago
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what is the resistance of a light bulb if a potential difference of 120 v will produce a current of 0.5 a in the bulb? 0.0042 0.
svlad2 [7]
R = V/I

R = 120 V/ 0.5 A

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You are sitting 3 m away from you friend who is watching a cartoon on his phone. How will the sound itensity change if your frie
Zinaida [17]

Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  $\frac{1}{0.06^2}$

                       = $3.6 \times 10^{-3}$ times

3 0
3 years ago
one of the four wave interactions is very important to how plants use light to grow. guess which interaction this is
KiRa [710]
The photosynthetic wave interaction between visible light and a photosensitive part of a plant is very important t how plants use light to grow. 
The frequency range and intensity levels of this light, I don't know. 

Maybe the above ???
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