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3 years ago

Pls help me Im struggling to do this.

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

7 0

Answer:

The first answer is that the exponents decrease by one in a patern

Step-by-step explanation:

You might be interested in

Find the volume of a cone with a diameter of 5.5 km

vagabundo [1.1K]

Answer:

$volume = \frac{1}{3} \pi {r}^{2} h \\ = \frac{1}{3} \times \frac{22}{7} \times {( \frac{5.5}{2}) }^{2} \times 11.2 \\ = 88.7 \: {km}^{3}$

4 0

3 years ago

Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each

Alinara [238K]

The answer is:
Justin weighs 165 pounds.
Greg weighs 180 pounds.

If:
j - Justin's weight
g - Greg's weight

Then the system of equations is:
j + 15 = g ⇒ g = j + 15
1/2g = j - 75 ⇒ j = 1/2g + 75

We can replace j in the first equation:
g = 1/2g + 75 + 15
g - 1/2g = 90
1/2g = 90
⇒ g = 90 ÷ 1/2 = 180

Thus, Greg weighs 180 pounds.

Now, using the first equation, we will calculate Justin's weight:
j + 15 = g ⇒ j = g - 15
g = 180

Thus
j = g - 15 = 180 - 15 = 165

Therefore, Justin weighs 165 pounds.

4 0

3 years ago

What is the value of g if 5(2-g)=0 ? * Your answer

Dovator [93]

Answer:

g = 2

Step-by-step explanation:

5(2-g) = 0

10 - 5g = 0

-5g = -10

g = -10/-5

= 2

3 0

4 years ago

For the past ten years, Michelle has been tracking the average annual rainfall in Boynton Beach, Florida by recording her data i

Sedbober [7]

Answer:

See explanation

Step-by-step explanation:

The average rainfall when you add all 10 years of rainfall up and divide by 10 is an average of 59.946 inches of rain each year. The equation for the data is y = -0.53x + 64.45, this means that the rainfall is getting less each year at a -0.53 inches of rain each year.

x = year (2004 would be 4, etc)

4 0

3 years ago

Suppose a normal distribution has a mean of 222 and a standard deviation of

Flura [38]

Answer:

C) 53.3%

The probability that a data value is between 206 and 230

P( 206 ≤X≤230) = 0.5328 = 53.3%

Step-by-step explanation:

Explanation

Given that Mean of the Normal distribution(μ) = 222

Given that the standard deviation of the Normal distribution (σ) = 16

Let 'X' be the random variable in the Normal distribution

we have to find that the probability that a data value is between 206 and 230

solution:-

Step(i):-

Let 'X' = 206

$Z = \frac{x^{-}-mean }{S.D} = \frac{206-222}{16} = -1$

Let X = 230

$Z = \frac{x-mean }{S.D} = \frac{230-222}{16} = 0.5$

Step(ii):-

The probability that a data value is between 206 and 230

P( 206 ≤X≤230) = P( -1≤Z≤0.5)

= |A(0.5)+A(-1)|

= 0.1915+0.3413

= 0.5328

final answer:-

The probability that a data value is between 206 and 230

P( 206 ≤X≤230) = 0.5328 = 53.3%

6 0

3 years ago