Question

ss legs. How many chickens are heterozygous for the “feathered leg” allele? Assume the population is in Hardy-Weinberg equilibrium. In chickens, having feathers on legs is dominant to having featherless legs. In a population of 200 chickens, 128 have featherless legs. How many chickens are heterozygous for the “feathered leg” allele? Assume the population is in Hardy-Weinberg equilibrium. 32 36 64 72 Not enough information is provided.

Answer 1

Answer:

Option A, $32$%

Explanation:

Number of chickens having featherless legs $= 128$

Number of chickens having feathered legs $= 200-128$$= 72$

Frequency of chickens having featherless legs

$= q^{2}$

$q^{2} = \frac{128}{200}\\q^{2} = 0.64$

Frequency of alleles for featherless legs

$= \sqrt{q^{2}} \\= \sqrt{0.64} \\= 0.8$

As per first equation of Hardy Weinberg-

$p+q=1$

Substituting the given values we get -

$p = 1-0.8\\p=0.2$

As per second equation of Hardy Weinberg-

$p^{2} + q^{2} + 2pq=1$

Substituting the given values we get -

$0.64+0.04+2pq=1\\2pq=1-(0.64+0.04)\\2pq= 0.32\\2pq=32$%