Answer:
let required no be x
![\frac{1}{7} = \frac{x}{42}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B7%7D%20%20%3D%20%20%5Cfrac%7Bx%7D%7B42%7D%20)
by doing crisscrossed multiplication
![42 \times 1 = 7 \times x](https://tex.z-dn.net/?f=42%20%5Ctimes%201%20%3D%207%20%5Ctimes%20x)
42=7x
dividing both side by 7
![\frac{42}{7} = 7x \div 7](https://tex.z-dn.net/?f=%20%5Cfrac%7B42%7D%7B7%7D%20%20%3D%207x%20%5Cdiv%207)
6=x
therefore x=6
therefore value of remaining no.is 6
Answer:
30 miles
Step-by-step explanation:
Given that:
Alex has some target to run a certain number of miles by the end of the month.
Goal already achieved = 40% of the total goal
Number of miles already run by Alex = 12 miles
To find:
Number of miles that Alex is trying to run by the end of month?
Solution:
We have to find nothing but the goal of Alex here.
Let the number of miles that Alex is trying to run by the end of the month =
miles
As per question statement:
40% of total number of miles to be run = 12 miles
OR
![\dfrac{40}{100}\times x = 12\\\Rightarrow 40x=12\times 100\\\Rightarrow x = \dfrac{1200}{40}\\\Rightarrow \bold{x = 30\ miles}](https://tex.z-dn.net/?f=%5Cdfrac%7B40%7D%7B100%7D%5Ctimes%20x%20%3D%2012%5C%5C%5CRightarrow%2040x%3D12%5Ctimes%20100%5C%5C%5CRightarrow%20x%20%3D%20%5Cdfrac%7B1200%7D%7B40%7D%5C%5C%5CRightarrow%20%5Cbold%7Bx%20%3D%2030%5C%20miles%7D)
Total number of miles that Alex is trying to run by the end of the month = <em>30 miles</em>
The answer is 28.07. I just took this test
Answer:
1.60 ![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area = ![\pi](https://tex.z-dn.net/?f=%5Cpi)
![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
So that,
for the inner part of the pipe,
r = ![\frac{diameter}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bdiameter%7D%7B2%7D)
= ![\frac{5}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D)
= 2.5 feet
Area of the inner part of the pipe = ![\pi](https://tex.z-dn.net/?f=%5Cpi)
![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
= 3.14 x ![(2.5)^{2}](https://tex.z-dn.net/?f=%282.5%29%5E%7B2%7D)
= 19.625
Are of the inner part of the pipe is 19.63
.
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r = ![\frac{5.2}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5.2%7D%7B2%7D)
= 2.6 feet
Area of the pipe = ![\pi](https://tex.z-dn.net/?f=%5Cpi)
![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
= 3.14 x ![(2.6)^{2}](https://tex.z-dn.net/?f=%282.6%29%5E%7B2%7D)
= 21.2264
Area of the pipe is 21.23
.
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60
.
Answer:
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Step-by-step explanation:
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