Question

Tìm X 3x2-3x×(x-2)-12=0

Answer 1

Answer:

$3x^2-3x\left(x-2\right)-12=0$

$3x^2-3x\left(x-2\right)-12+12=0+12 \longleftarrow (\mathrm{Add\:}12\mathrm{\:to\:both\:sides})$

$3x^2-3x\left(x-2\right)=12$

$-3x\left(x-2\right)=-3xx-\left(-3x\right)\cdot \:2$

$=-3xx+3\cdot \:2x$

$-3xx+3x^{2}$

$=3x^{1+1}$

$=3x^2$

$3\cdot \:2x=6x$

$=-3x^2+6x$

$3x^2-3x^2+6x=12\Longleftarrow Add\:similar\:elements$

$6x=12$

$\frac{6x}{6}=\frac{12}{6} \Longleftarrow Divide$

$x=2$

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OAmalOHopeO

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