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rodikova [14]
2 years ago
11

Tìm X 3x2-3x×(x-2)-12=0

Mathematics
1 answer:
Rama09 [41]2 years ago
5 0

Answer:

3x^2-3x\left(x-2\right)-12=0

3x^2-3x\left(x-2\right)-12+12=0+12 \longleftarrow (\mathrm{Add\:}12\mathrm{\:to\:both\:sides})

3x^2-3x\left(x-2\right)=12

-3x\left(x-2\right)=-3xx-\left(-3x\right)\cdot \:2

=-3xx+3\cdot \:2x

-3xx+3x^{2}

=3x^{1+1}

=3x^2

3\cdot \:2x=6x

=-3x^2+6x

3x^2-3x^2+6x=12\Longleftarrow Add\:similar\:elements

6x=12

\frac{6x}{6}=\frac{12}{6} \Longleftarrow Divide

x=2

✧✧✧✧✧✧✧✧

OAmalOHopeO

✧✧✧✧✧✧✧✧

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