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Licemer1 [7]
3 years ago
12

Help me with this very pls. I will give you the brainliest and a thanks!! :)) Can you do 1 and 4 thanks!! :)))

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0
Answer: 1. 12 and 4 I think
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Answer:

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Step-by-step explanation:

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Use Cramer’s Rule to solve system of equation.
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\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

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Which equation is an identity?
spayn [35]
7z + 10 - z = 8z - 2(z - 5)
7z + 10 - z = 8z - 2z + 10
6z + 10 = 6z + 10
6z - 6z = 10 - 10
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Therefore, 7z + 10 - z = 8z - 2(z - 5)
3 0
3 years ago
Write the equation of the graphed in NO SPACES ALL LOWERCASE<br> Help !!
cupoosta [38]

Answer:

The equation of the graphed line is:

  • y = 2

Step-by-step explanation:

From the graph, it is clear that the line is a horizontal line at y = 2.

We know that a horizontal line has a slope of 0 because the value of y does not change no matter what the value of x we put in.

In other words, the equation of the horizontal line would always get the form:

y = k

where k is the y-intercept of the line.

Determining the y-intercept of the line:

We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

From the graph, it is clear

at x = 0, y = 2

Thus, the y-intercept k = 2

Thus, if we substitute the y-intercept k = 2 in the equation y = k, we get the equation

y = 2

Therefore, the equation of the graphed line is:

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