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DanielleElmas [232]
3 years ago
7

Why does it take 10 copies of 1 sixth to make the same amount as five copies of 1 third explain your answer in words and picture

s?
Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0
10 is double of 5
6 is double of 3

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Find the zeros of the polynomial x2-7​<br><br>please answer step by step
Yuki888 [10]

Answer:

x = ± \sqrt{7}

Step-by-step explanation:

To find the zeros equate the polynomial to zero, that is

x² - 7 = 0 ( add 7 to both sides )

x² = 7 ( take the square root of both sides )

x = ± \sqrt{7}

Thus the exact solutions are

x = - \sqrt{7} , x = \sqrt{7}

6 0
3 years ago
Grace bought 6.9 ounces of chocolate. 0.7 ounces of it was milk chocolate and the rest was dark chocolate. How much dark chocola
goblinko [34]
6.2 you subtract the 0.7 from 6.9 because 0.7 of it is milk chocolate
7 0
3 years ago
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NEED HELP FAST!!!!!!!Consider the right triangle below. A right triangle with a hypotenuse with length 6.5 feet, and side length
gulaghasi [49]

Answer:

Perimeter: 15 feet, Area: 15 square feet.

Step-by-step explanation:

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8 0
3 years ago
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What is the equation of the line?
ZanzabumX [31]
I would say...
y = 4/-3 + -3
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3 years ago
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Find the first four terms of the sequence given ai<br> 31 and an+1<br> an<br> 3.
Leno4ka [110]

Answer:

he arithmetic sequence ai is defined by the formula: a1= 2 ai= ai - 1 -3 find the sum of the first 335 terms in the sequence

Step-by-step explanation:

In an arithmetic sequence,

a_1=2a

1

=2

a_i=a_{i-1}-3a

i

=a

i−1

−3

To find:

The sum of the first 335 terms in the given sequence.

Solution:

The recursive formula of an arithmetic sequence is:

a_i=a_{i-1}+da

i

=a

i−1

+d ...(i)

Where, d is the common difference.

We have,

a_i=a_{i-1}-3a

i

=a

i−1

−3 ...(ii)

On comparing (i) and (ii), we get

d=-3d=−3

The sum of first i terms of an arithmetic sequence is:

S_i=\dfrac{i}{2}[2a+(i-1)d]S

i

=

2

i

[2a+(i−1)d]

Putting i=335,a=2,d=-3i=335,a=2,d=−3 , we get

S_{335}=\dfrac{335}{2}[2(2)+(335-1)(-3)]S

335

=

2

335

[2(2)+(335−1)(−3)]

S_{335}=\dfrac{335}{2}[4+(334)(-3)]S

335

=

2

335

[4+(334)(−3)]

S_{335}=\dfrac{335}{2}[4-1002]S

335

=

2

335

[4−1002]

S_{335}=\dfrac{335}{2}(-998)S

335

=

2

335

(−998)

On further simplification, we get

S_{335}=335\times (-499)S

335

=335×(−499)

S_{335}=-167165S

335

=−167165

Therefore, the sum of the first 335 terms in the given sequence is -167165.

7 0
3 years ago
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