Answer:
tan (A-B) = ± 4/3
Step-by-step explanation:
COS (A-B) = 3/5
COS² (A-B) = (3/5)² = 9/25 = 1 - sin² (A-B)
sin² (A-B) = 1 - 9/25 = 16/25
sin (A-B) = ± 4/5
tan (A-B) = sin (A-B) / cos (A-B) = (± 4/5) / (3/5) = ± 4/3
9514 1404 393
Answer:
2
Step-by-step explanation:
Each image point is twice as far from the origin as its preimage point. Each image segment is twice as long as its preimage segment. (LM=2, L'M'=4, for example)
The scale factor is 2.
Answer:
Step-by-step explanation:
27 is the "center" of a range of measurements of the height of the guard rail. The height could be as much as 30 inches or as little as 24 inches. The absolute value operator encloses "x - 27," where 27 is the "center." The acceptable excess or acceptable deficiency is 3 inches.
So now we can eliminate possible answers B and C, in both cases because 27 is inappropriately greater than 3.
Narrowing down our choices, we have h + 27 and h - 27 inside the absolute value operator. 27 is a positive quantity (height of the guard rail), so the inequality showing +27 as the "center" is correct; that is
D: |h - 27| ≤ 3 (measurements in inches).
Answer:(2.2).
Step-by-step explanation:
Answer:
b)
Step-by-step explanation:
A is invertible if and only if det(A)≠0. Let's compute the determinant of A and find the values k for which it is nonzero.
Using Sarrus's rule, we obtain that
Note that the determinant is a quadratic equation on k, which can be factored as above.
Now the determinant is only zero if k=5 or k=2 (the zeroes of the quadratic polynomial). Therefore, if k≠2,5 the determinant is nonzero so A is invertible.
