Answer:
1300
Step-by-step explanation:
Let the amount put in the station's tank = x
4(400 + x) = 8100 - x Remove the brackets
1600 + 4x = 8100 - x Subtract 1600 from both sides
1600 - 1600 + 4x = 8100 - 1600 - x Do the subtraction
4x = 6500 - x Add x to both sides
4x + x = 6500 - x + x
5x = 6500 Divide by 5
5x/5 = 6500/5
x = 1300
1300 gallons were added to the station's tank.
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
Answer:
See attachment for plot
Step-by-step explanation:
Given
--- increment in the rate
First, we need to model the new rate
A linear equation is:
Where
Compare and . we have:
The above represents the previous rate.
The new rate:
Rewrite as:
So, the model is:
<u>The plot at 1 and 2 minutes</u>
When 
When 
So, we have:
<em>Whether she moves backwards or forward, the distance covered remains the same</em>
<em>See attachment for plot</em>
82.4+108.6=191 and 12052.1 divided by 191=63.1
So the answer is 63.1
