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GenaCL600 [577]
3 years ago
11

Can u all help with these plzz

Mathematics
2 answers:
jeyben [28]3 years ago
6 0
Use coucalater and divide and multiply and add and ya for them
Goshia [24]3 years ago
3 0
Answer:
11. D
12. A

step-by-step explanation:
11. using pemdas
(6/3) • 4 + 8
2 • 4 + 8
8 + 8
16 false
27 - 9/3 • (4 + 1)
27 - 3 • 5
27 - 15
12 false
(18 + 12) • 6 - 4
30 • 6 - 4
180 - 4
176 false
71 - 5 • (9 + 4)
71 - 5 • 13
71 - 65
6 true
12.
60 is divisible by 6 (60/6 = 10), 2 (60/2 = 30), and 3 (60/3 = 20)
33 is only divisible by 3 (33/3 = 11)
46 is only divisible by 2 (46/2 = 23)
21 is only divisible by 3 (21/3 = 8)
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Tcecarenko [31]

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7 0
3 years ago
What kind of decimal is an irrational number give an example
Nana76 [90]

Answer:

An irrational decimal is a decimal that cannot be written in fraction form

Ex: Pi or any decimal that keeps going and doesn't repeat

Step-by-step explanation:

I would give you more examples but they are all really long numbers and go on forever.

3 0
3 years ago
Read 2 more answers
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Alecsey [184]
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4 0
3 years ago
If you know how to solve this, Please answer it. Thank You
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3 0
3 years ago
Find an equation for the nth term of the arithmetic sequence.
Irina18 [472]

Answer:

The equation of the nth term is an = -621 + 42n

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive numbers

- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

  between each two consecutive terms

, n is the position of the term

* Lets solve the problem

∵ an = a + (n - 1)d

∴ a14 = a + (14 - 1)d

∴ a14 = a + 13d

∵ a14 = -33

∴ a + 13d = -33 ⇒ (1)

- Similar we can find another equation from a15

∵ a15 = a + (15 - 1)d

∴ a15 = a + 14d

∵ a15 = 9

∴ a + 14d = 9 ⇒ (2)

- We will solve equations (1) and (2) to find a and d

* Lets subtract equation (2) from equation (1)

∴ (a - a) + (13 - 14)d = (-33 - 9)

∴ -d = -42 ⇒ × both sides by -1

∴ d = 42

- Substitute this value of d in equation (1) or (2)

∵ a + 13d = -33

∵ d = 42

∴ a + 13(42) = -33

∴ a + 546 = -33 ⇒ subtract 546 from both sides

∴ a = -579

* Now lets write the equation of the nth term

∵ an = a + (n - 1)d

∵ a = -579 and d = 42

∴ an = -579 + (n - 1) 42 ⇒ open the bracket

∴ an = -579 + 42n - 42

∴ an = -621 + 42n

* The equation of the nth term is an = -621 + 42n

6 0
3 years ago
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