Suppose a triangle has sides a, b, and c let theta be the angle opposite the side of length a. If cos theta < 0 The statement that is true is <span>b^2+c^2>a^2. The answer is letter A.</span>
That would be the cube root of (x+5)^11.
If desired, this could be reduced to the cube root of (x+5)^9*(x+5)^2, which would be
(x+5)^3*(x+5)^(2/3)
7/15, 0.65, .0715
7/15 = .467
Hope this helps you! (:
-PsychoChicken4040
Area = 1/2 x base x height
Let the height be x.
Height = x
Base = 2x
Area of triangle = 1/2 x base x heght
Plug base and height into the variables:
(1/2)(2x)(x) = 196
Combine like terms:
x² = 196
Square root both sides:
x = 14
Find Base and height:
Base = x = 14 km
Height = 2x = 2(14) = 28 km
Answer: Height = 28km
Answer:
745.44 square mm
Step-by-step explanation:
The figure can be decomposed into ...
- a semicircle of radius 12.5 mm
- a rectangle 12.5 mm by 25 mm
- a triangle 12.5 mm by 30 mm
The relevant area formulas are ...
Semicircle: A = 1/2πr² = 1/2π(12.5 mm)² ≈ 245.437 mm²
Rectangle: A = LW = (12.5 mm)(25 mm) = 312.500 mm²
Triangle: A = 1/2bh = 1/2(12.5 mm)(30 mm) = 187.500 mm²
Total area of the figure is ...
245.437 +312.500 +187.500 = 745.437 . . . mm²
The area of the figure is about 745.44 square mm.