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GenaCL600 [577]
3 years ago
11

Can u all help with these plzz

Mathematics
2 answers:
jeyben [28]3 years ago
6 0
Use coucalater and divide and multiply and add and ya for them
Goshia [24]3 years ago
3 0
Answer:
11. D
12. A

step-by-step explanation:
11. using pemdas
(6/3) • 4 + 8
2 • 4 + 8
8 + 8
16 false
27 - 9/3 • (4 + 1)
27 - 3 • 5
27 - 15
12 false
(18 + 12) • 6 - 4
30 • 6 - 4
180 - 4
176 false
71 - 5 • (9 + 4)
71 - 5 • 13
71 - 65
6 true
12.
60 is divisible by 6 (60/6 = 10), 2 (60/2 = 30), and 3 (60/3 = 20)
33 is only divisible by 3 (33/3 = 11)
46 is only divisible by 2 (46/2 = 23)
21 is only divisible by 3 (21/3 = 8)
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You’re about to get on a plane to Seattle. You want to know if it’s raining. You call 3 random friends who live there and ask ea
Lyrx [107]

Answer:

The probability that it is actually raining in Seattle is 26/27

Step-by-step explanation:

Here we have the probability that a friend is telling the truth = 2/3

The probability that a friend is telling a lie = 1/3

Therefore, if all three friends say "Yes" it is raining in Seattle, the probability that is actually raining is given by the probability that one of them is telling the truth. That is the complement that all are messing with their friend.

The probability that all are not telling the truth is;

P(All not telling the truth) = \frac{1}{3} \times \frac{1}{3}   \times  \frac{1}{3}  =  \frac{1}{27}

P(One is telling the truth) = 1 - P(All not telling the truth)  = 1- \frac{1}{27} = \frac{26}{27}

Therefore, the probability that it is actually raining in Seattle = 26/27.

3 0
3 years ago
Which of the algebraic expressions are not linear expressions? Select all that apply. a. 3x - 2 b. -9y c. -7x^2^ + 4x d. -1/2x^2
Sedaia [141]

Answer:

c, d and e

Step-by-step explanation:

A linear expression is an expression in which sum of exponents of variables is at most 1 in each of its terms.

Option a: 3x - 2

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option b: -9y

Here, the exponent of the variable is 1.

So, it is a linear expression.

Option c: -7x^2 + 4x

Here, the highest exponent of the variable is 2.

So, it is NOT a linear expression.

Option d: -\frac{1}{2} x^2

Here, the exponent of the variable is 2.

So, it is NOT a linear expression.

Option e: 8xy

Here, sum of exponents of variables is 2.

So, it is NOT a linear expression.

Hence, c, d and e are NOT algebraic expressions.

6 0
3 years ago
The volume of cylinder is 448 pie cm cube and height 7 cm find its radius<br>​
Verizon [17]

<u>Answer:</u>

r =\bf 8 \space\ cm

<u>Step-by-step explanation:</u>

The formula for volume of a cylinder is as follows:

\boxed{Volume = \pi r^2 h}

where:

• r = radius (? cm)

• h = height (7 cm).

Substituting the values into the formula:
448 \pi  = \pi \times r^2 \times 7

Now solve for r:

⇒ r^2 = \frac{448 \pi }{\pi \times 7}

⇒ r = \sqrt{64}

⇒ r =\bf 8 \space\ cm

8 0
2 years ago
Read 2 more answers
I WILL GIVE 100 POINTS TO ANYONE WHO CAN HELP ME WITH THIS PROBABILITY QUESTION
zhuklara [117]

Answer:

do u have answer choices or did u come up with anything that can help me out a lil bit

Step-by-step explanation:

mrk me brainliest plz

7 0
2 years ago
A cable car starts off with n riders. The times between successive stops of the car are independent exponential random variables
nikitadnepr [17]

Answer:

The distribution is \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}

Solution:

As per the question:

Total no. of riders = n

Now, suppose the T_{i} is the time between the departure of the rider i - 1 and i from the cable car.

where

T_{i} = independent exponential random variable whose rate is \lambda

The general form is given by:

T_{i} = \lambda e^{- lambda}

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:

S_{n} = T_{1} + T_{2} + ........ + T_{n}

S_{n} = \sum_{i}^{n} T_{n}

Now, the sum of the exponential random variable with \lambda with rate \lambda is given by:

S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}

5 0
3 years ago
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